百钱百鸡问题

方法一：                                                     

#include <stdio.h>

int main()
{
int cock,hen,chicken;
for(cock=0;cock<20;cock++)
for(hen=0;hen<=33;hen++)
for(chicken=0;chicken<100;chicken++)

{if((cock+chicken+hen==100)&&(5*cock+3*hen+chicken/3.0==100))
printf("cock=%2d,hen=%2d,chicken=%2d\n",cock,hen,chicken);}
return 0;
}

方法二：

#include <stdio.h>

int main()
{
int cock,hen,chicken;
for(cock=0;cock<20;cock++)
for(hen=0;hen<=33;hen++)
{chicken=100-cock-hen;

 

if(5*cock+3*hen+chicken/3.0==100)
printf("cock=%2d,hen=%2d,chicken=%2d\n",cock,hen,chicken);}
return 0;
}

总结：方法一计算次数要多，但相比方法二稍微好理解