C# 基础 - Json 之间的转换

这里举例两种方式。

1. Newtonsoft.Json.JsonConvert

需要引用外部的 Newtonsoft.Json.dll

/// <summary>
/// 将json字符串转换为对象(使用Json.net)
/// </summary>
/// <param name="response"></param>
/// <param name="dateformatstring">时间格式</param>
/// <returns></returns>
public T JsonNetConvertJson<T>(string response)
{
    try
    {
        //return JsonConvert.DeserializeObject<T>(response);
        JsonSerializerSettings jsSetting = new JsonSerializerSettings();
        jsSetting.NullValueHandling = NullValueHandling.Ignore;
        return JsonConvert.DeserializeObject<T>(response, jsSetting);   
    }
    catch (Exception ex)
    {
        WriteLog.WriteLogger.Error("将json字符串转换为对象出错!\r\njson为:" + response, ex);
        return default(T);
    }
}

Newtonsoft.Json.JsonSerializerSettings 是对返回数据的一些默认转换.

空值设置:
NullValueHandling 枚举默认是 Include,如果有 int 类型的字段是 null,会报错,把 JsonSerializerSettings.NullValueHandling 设置为 NullValueHandling.Ignore 之后,就会忽略值为 null 的字段。

时间设置:
setting.DateFormatHandling = DateFormatHandling.MicrosoftDateFormat;
setting.DateFormatString = "yyyy-MM-dd HH:mm:ss";

2. System.Runtime.Serialization.Json.DataContractJsonSerializer

/// <summary>
/// 将json字符串转换为对象(使用DataContractJsonSerializer)
/// </summary>
/// <param name="response"></param>
/// <param name="dateformatstring">时间格式</param>
/// <returns></returns>
public T ConvertJson<T>(string response)
{
    try
    {
        DataContractJsonSerializer Serializer = new DataContractJsonSerializer(typeof(T));
        using (MemoryStream stream = new MemoryStream(Encoding.UTF8.GetBytes(response)))
        {
            return (T)Serializer.ReadObject(stream);
        }
    }
    catch (Exception ex)
    {
        WriteLog.WriteLogger.Error("将json字符串转换为对象出错!\r\njson为:" + response, ex);
        return default(T);
    }
}
posted @ 2021-03-03 19:25  鑫茂  阅读(388)  评论(0编辑  收藏  举报