234. Palindrome Linked List

 

Example 1:

Input: head = [1,2,2,1]
Output: true

Example 2:

Input: head = [1,2]
Output: false
public boolean isPalindrome(ListNode head) {
ListNode mid = getMid(head);
ListNode headSecond = reverseList(mid);

while(head != null && headSecond != null){
if(head.val != headSecond.val){
return false;
}
head = head.next;
headSecond = headSecond.next;
}
return true;
}

public ListNode getMid(ListNode head){
ListNode slow = head;
ListNode fast = head;

while(fast!= null && fast.next != null){
slow = slow.next;
fast = fast.next.next;
}

return slow;
}

public ListNode reverseList(ListNode node){

// 反转链表部分可参考 反转链表
}
posted @ 2022-11-27 16:59  MarkLeeBYR  阅读(22)  评论(0)    收藏  举报