102. Binary Tree Level Order Traversal

Solution 1:
class Solution {
    public List<List<Integer>> levelOrder(TreeNode root) {
        Queue<TreeNode> queue = new LinkedList<>();
        List<List<Integer>> wrapList = new LinkedList<>();
        if(root == null) 
            return wrapList;
        queue.offer(root);
        while (!queue.isEmpty()) {
            int levelNum = queue.size();
            List<Integer> subList = new LinkedList<>();
            for(int i = 0; i < levelNum; i++) {
              TreeNode n = q.poll();  
        if(n.left != null) q.add(n.left);
                if(n.right != null) q.add(n.right);
                subList.add(n.val);
            }
            wrapList.add(subList);
        }
        return wrapList;
    }
}
 
//如果要求把null节点也列出来:
public static List<List<Integer>> levelOrder(TreeNode root) {
    Queue<TreeNode> queue = new LinkedList<>();
    List<List<Integer>> wrapList = new LinkedList<>();
    if(root == null)
        return wrapList;
    queue.offer(root);
    while (!queue.isEmpty()) {
        int levelNum = queue.size();
        List<Integer> subList = new LinkedList<>();
        for(int i = 0; i < levelNum; i++) {
            TreeNode tn = queue.poll();
            if(tn != null)
                queue.offer(tn.left);
            if(tn != null)
                queue.offer(tn.right);
            if (tn == null)
                subList.add(null);
            else
                subList.add(tn.val);
        }
        wrapList.add(subList);
    }
    return wrapList;
}
 
 
Solution 2:
class Solution {
   public List<List<Integer>> levelOrder(TreeNode root) {
        List<List<Integer>> res = new ArrayList<>();
        levelHelper(res, root, 0);
        return res;
    }
    
    public void levelHelper(List<List<Integer>> res, TreeNode root, int height) {
        if (root == null) return;
        if (height >= res.size()) {
            res.add(new LinkedList<>());
        }
        res.get(height).add(root.val);
        levelHelper(res, root.left, height+1);
        levelHelper(res, root.right, height+1);
    }
}
posted @ 2022-11-19 18:58  MarkLeeBYR  阅读(18)  评论(0)    收藏  举报