AtCoder Beginner Contest 173 B - Judge Status Summary

B - Judge Status Summary

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Time Limit: 2 sec / Memory Limit: 1024 MB

Score : $200200$ points

Problem Statement

Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.

The problem has $\mathrm{NN}$ test cases.

For each test case $\mathrm{ii}$ ($\mathrm{1\le i\le N1\le i\le N}$), you are given a string ${\mathrm{SiSi}}^{}$ representing the verdict for that test case. Find the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively.

See the Output section for the output format.

Constraints

• $\mathrm{1\le N\le 1051\le N\le 105}$
• ${\mathrm{SiSi}}^{}$ is AC, WA, TLE, or RE.

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Input

Input is given from Standard Input in the following format:

$\mathrm{NN}$
${\mathrm{S1S1}}^{}$
$⋮⋮$
${\mathrm{SNSN}}^{}$

Output

Let ${\mathrm{C0}}^{}$, ${\mathrm{C1}}^{}$, ${\mathrm{C2C2}}^{}$, and ${\mathrm{C3}}^{}$ be the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively. Print the following:

AC x ${\mathrm{C0}}^{}$
WA x ${\mathrm{C1}}^{}$
TLE x ${\mathrm{C2}}^{}$
RE x ${\mathrm{C3}}^{}$

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Sample Input 1 Copy

Copy

6
AC
TLE
AC
AC
WA
TLE

Sample Output 1 Copy

Copy

AC x 3
WA x 1
TLE x 2
RE x 0

We have $33$, $11$, $22$, and $00$ test case(s) for which the verdict is AC, WA, TLE, and RE, respectively.

解题思路：小学计数问题，不过多解释，看题目就能懂

解法1，利用字符串模拟：

#include<cstdio>
#include<cstring>
using namespace std;
int main(void)
{
    int n;
    int a[4];
    char ch[10];
    char str[4][10]={{"AC"},{"WA"},{"TLE"},{"RE"}};
    while(~scanf("%d",&n))
    {
        memset(a,0,sizeof(a));
        getchar();
        for(int i=0;i<n;++i)
        {
            scanf("%s",ch);
            for(int j=0;j<4;++j)
            {
                if(strcmp(ch,str[j])==0)
                a[j]++;
            }
        }
        for(int i=0;i<4;++i)
            printf("%s x %d\n",str[i],a[i]);
    }
    
    return 0;
}

解法2，利用STL的map：

#include<iostream>
#include<cstdio>
#include<map>
using namespace std;
int main(void)
{
    ios::sync_with_stdio(false);
    map<string,int> mp;
    int n;
    char ch[10];
    while(cin>>n)
    {
        for(int i=0;i<n;++i)
        cin>>ch,mp[ch]++;
        printf("AC x %d\n",mp["AC"]);
        printf("WA x %d\n",mp["WA"]);
        printf("TLE x %d\n",mp["TLE"]);    
        printf("RE x %d\n",mp["RE"]);
    }
    return 0;
}