You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

非常经典的dp问题,每次做都有不同的理解。

public class Solution {
    public int climbStairs(int n) {
        int[] dp=new int[n+1];
        dp[0]=1;
        dp[1]=1;
        for(int i=2;i<=n;i++)
        {
            dp[i]=dp[i-1]+dp[i-2];
        }
        return dp[n];
    }
}

 

posted on 2016-09-15 12:25  Machelsky  阅读(102)  评论(0)    收藏  举报