ural 1067 && poj 1760 Disk Tree(字典树+模拟)

http://acm.timus.ru/problem.aspx?space=1&num=1067

　　这题是模拟一个目录，我用到字典树来做这题。

　　这题我是用大量stl来减少代码量，不过我对stl的功能并不是完全的熟悉，所以用起来有点别扭，代码时间也大约用了半个多小时，不过最后稳稳的1y了！～

参考代码：

View Code

  1 #include <cstdio>
  2 #include <cstdlib>
  3 #include <cstring>
  4 #include <algorithm>
  5 #include <vector>
  6 
  7 using namespace std;
  8 
  9 struct Node;
 10 struct Cata;
 11 typedef vector<Cata> vc;
 12 
 13 struct Cata {
 14     char name[10];
 15     Node *next;
 16 
 17     bool operator < (const Cata &x) const {
 18         return strcmp(name, x.name) < 0;
 19     }
 20 } ;
 21 struct Node {
 22     vc child;
 23 
 24     Node() {
 25         child.clear();
 26     }
 27 } *Root;
 28 
 29 void insert(char *p) {
 30     char tmp[10];
 31     char *q = tmp;
 32     Node *cur = Root;
 33     Cata buf;
 34     vc::iterator ii;
 35 
 36     while (true) {
 37         while (*p && *p != '\\') {
 38             *q = *p;
 39             q++, p++;
 40         }
 41         *q = 0;
 42 //        puts(tmp);
 43 
 44         for (ii = cur->child.begin(); ii != cur->child.end(); ii++) {
 45             if (!strcmp((*ii).name, tmp)) {
 46                 if (!(*ii).next) {
 47                     (*ii).next = new Node();
 48                 }
 49                 cur = (*ii).next;
 50                 break;
 51             }
 52         }
 53 //        puts("???");
 54         if (ii == cur->child.end()) {
 55             buf.next = new Node();
 56             strcpy(buf.name, tmp);
 57             cur->child.push_back(buf);
 58             cur = buf.next;
 59 //            puts("yeah~");
 60         }
 61 
 62         if (*p) {
 63             q = tmp;
 64             p++;
 65         } else {
 66             break;
 67         }
 68     }
 69 }
 70 
 71 void print(int depth, Node *rt) {
 72     if (!rt) return ;
 73 
 74     vc::iterator ii;
 75 
 76     sort(rt->child.begin(), rt->child.end());
 77     for (ii = rt->child.begin(); ii != rt->child.end(); ii++) {
 78         for (int i = 0; i < depth; i++) {
 79             putchar(' ');
 80         }
 81         puts((*ii).name);
 82         print(depth + 1, (*ii).next);
 83     }
 84 }
 85 
 86 int main() {
 87     char buf[100];
 88     int n;
 89 
 90 //    freopen("in", "r", stdin);
 91     while (~scanf("%d", &n)) {
 92         Root = new Node();
 93         while (n--) {
 94             scanf("%s", buf);
 95             insert(buf);
 96         }
 97         print(0, Root);
 98     }
 99     return 0;
100 }

——written by Lyon

posted @ 2012-10-31 02:11 LyonLys 阅读(400) 评论(0) 收藏举报

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