hdu As Easy As A+B

纯水题 ,不解释

#include<stdio.h>
int t,n,num[1005];
int main( )
{
    scanf( "%d",&t );
    while( t-- )
    {
           scanf( "%d",&n );
           for( int i = 0; i < n; ++i )
                scanf( "%d",&num[i] );
           for( int i = 0,f = 1; i < n; ++i )
                for( int j = 1; j < n - i; ++j )
                     if( num[j-1] > num[j] )
                         num[j-1] ^= num[j] ^= num[j-1] ^= num[j];
           for( int i = 0; i < n; ++i )
                printf( i != n - 1?"%d ":"%d\n",num[i] ); 
           }
    return 0;
}