摘要:
[{'name1':'Jack'},{'name2':'Lara'}] >得到[name1, name2]for循环嵌套,列表生成式写法: alist=[{'name1':'Jack'},{'name2':'Lara'}] b = [j for one in alist for j in one] 阅读全文
摘要:
dict1={'name':'Lara','age':18} #判断键在不在字典中 for one in dict1: if 'name' in dict1:#或dict1.keys() print('key在字典中!') break #判断值在不在字典中 for one in dict1: if 阅读全文