mySQL--找出各科最高成绩

//找出各科最高成绩
create table gradeMax(
id int primary key auto_increment,
name varchar(20),
subject varchar(20),
grade int
);

insert into gradeMax(name ,subject ,grade ) values
('小点','java',99),
('小黑','.net',100),
('小军','职业素养',100),
('小王','语文',78),
('小憋','数学',96),
('小丽','英语',87);

select * from gradeMax
where GRADE =(select max(grade) from gradeMax where name=name);

select subject,max(grade),min(grade),sum(grade),avg(grade),count(grade) from gradeMax group by subject;

主要:
select * from gradeMax where grade in(select max(grade) from gradeMax group by subject);

select * from gradeMax where subject,grade in gradeMax ;

 

 

 

posted @ 2017-11-08 20:09  L伟铭  阅读(6921)  评论(2编辑  收藏  举报