python中一个简单的webserver

 python中一个简单的webserver 2013-02-24 15:37:49

分类： Python/Ruby

 

支持多线程的webserver

 

 
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#!/usr/bin/python
from SocketServer import ThreadingMixIn
from BaseHTTPServer import HTTPServer,BaseHTTPRequestHandler
 
class myHandler(BaseHTTPRequestHandler):
    #Handler for the GET requests
    def do_GET(self):
        self.send_response(200)
        self.send_header('Content-type','text/html')
        self.send_header('Uri',self.path)
        self.end_headers()
        self.wfile.write("hi multi threading test!\n")
 
  
class ThreadingHttpServer(ThreadingMixIn, HTTPServer):
    pass
PORT_NUM=8080
serverAddress=("", PORT_NUM)
server=ThreadingHttpServer(serverAddress, myHandler)
print 'Started httpserver on port ' , PORT_NUM
server.serve_forever()

 

 

测试：

curl -v http://127.0.0.1:8080/

 

 

 
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[root@localhost ~]# curl -v http://127.0.0.1:8080/
* About to connect() to 127.0.0.1 port 8080
*   Trying 127.0.0.1... connected
* Connected to 127.0.0.1 (127.0.0.1) port 8080
> GET / HTTP/1.1
> User-Agent: curl/7.15.5 (x86_64-redhat-linux-gnu) libcurl/7.15.5 OpenSSL/0.9.8b zlib/1.2.3 libidn/0.6.5
> Host: 127.0.0.1:8080
> Accept: */*
>
< HTTP/1.0 200 OK
< Server: BaseHTTP/0.3 Python/2.4.3
< Date: Sun, 24 Feb 2013 07:28:46 GMT
< Content-type: text/html
< Uri: /
hi multi threading test!
* Closing connection #0
posted @ 2014-06-30 01:56  kissing狐  阅读(385)  评论(0)    收藏  举报