[续]C#使用反射得到属性然后创建xml文档

续上一篇中,在方法二GetModelsFromXml中需要知道实体的具体类型,后来我发现可以使用object代替,结果成功了,现将修改的方法如下:

 

   /// <summary>
        
/// 将xml文档序列化为实体对象
        
/// </summary>
        
/// <param name="file">文件路径</param>
        
/// <returns></returns>
        public static List<Object> GetModelsFromXml(string file, Type type)
        {
            List<Object> list = null;
            if (File.Exists(file))
            {
                list = new List<Object>();
                //解析xml
                XmlDocument doc = new XmlDocument();
                doc.Load(file);
                String root = type.Name.ToLower() + "s";
                XmlNode rootNode = doc.SelectSingleNode(root);
                XmlNodeList nodes = rootNode.ChildNodes;
                foreach (XmlNode item in nodes)
                {
                    object obj = type.Assembly.CreateInstance("toolkit.Person");//注意这里必须是全类名
                    PropertyInfo[] pi = type.GetProperties();
                    XmlNodeList childs = item.ChildNodes;
                    //遍历子节点 
                    for (int i = 0; i < childs.Count; i++)
                    {
                        XmlNode n = childs[i];
                        //查找属性名称和xml文档中一致的节点名称,并且设置属性值
                        List<PropertyInfo> ps = pi.Where(p => p.Name.ToLower() == n.Name).ToList();
                        ps[0].SetValue(obj, n.InnerText.ToString(), null);
                    }
                    list.Add(obj);
                }
            }
            return list;
        }

调用的代码如下:

 

   List<object> persons = new List<object>();
                persons.AddRange(new Person[]{
                new Person(){Id="1",Name="jay",Age="23",Sex="male"},
                new Person(){Id="2",Name="lucy",Age="20",Sex="female"},
                new Person(){Id="3",Name="mike",Age="22",Sex="male"}});
                Toolkit.CreateXmlByModel(persons, "C:/Users/liyong/Desktop/1.xml""utf-8");
               persons=Toolkit.GetModelsFromXml("C:/Users/liyong/Desktop/1.xml",typeof(Person));
               foreach (var item in persons)
               {
                   Console.WriteLine(item.ToString());
               }

结果输出:

posted @ 2012-09-15 09:03  流星剑  阅读(686)  评论(0编辑  收藏  举报