Java JPA新增数据生成UUID


@Data
@AllArgsConstructor
@NoArgsConstructor
@Entity
@Table(name = "ek_office_info")
public class OfficeInfo {
    @Id
    @GenericGenerator(name = "generator", strategy = "uuid")
    @GeneratedValue(generator = "generator")
    @Column(name = "guid",nullable = false,length = 36)
    private String guid;

}

 

posted @ 2020-06-05 15:53  敲代码的机车Boy  阅读(677)  评论(0编辑  收藏  举报