java-回文问题

import java.util.Scanner;
public class Number {
   public static void main(String args[]) {
       int number,d5,d4,d3,d2,d1;
       Scanner reader = new Scanner(System.in);
       System.out.println("输入一个1至99999之间的数");
       number = reader.nextInt();
       if(number>0 && number<100000)      //判断number在1至99999之间的条件
           {    d5=number%100000/10000;   //计算number的最高位（万位）d5
                d4=number%10000/1000;     //计算number的千位d4
                d3=number%1000/100;       //计算number的百位d3
                d2=number%100/10;
                d1=number%10;
                if(d5!=0)                 //判断number是5位数的条件
                {  System.out.println(number+"是5位数");
                   if(d5==d1&&d4==d2)     //判断number是回文数的条件
                   {   System.out.println(number+"是回文数");
                   }
                   else
                   {   System.out.println(number+"不是回文数");
                   }
                }
                else if(d4!=0)            //判断number是4位数的条件
                {  System.out.println(number+"是4位数");
                   if(d5==d1&&d2==d4)    //判断number是回文数的条件码
                   {  System.out.println(number+"是回文数");
                   }
                  else
                   {  System.out.println(number+"不是回文数");
                   }
                }
                else if(d3!=0)           //判断number是3位数的条件
                {  System.out.println(number+"是3位数");
                   if(d1==d3)            //判断number是回文数的条件
                   {  System.out.println(number+"是回文数");
                   }
                  else
                   {  System.out.println(number+"不是回文数");
                   }
                }
                else if(d2!=0)
                {  System.out.println(number+"是2位数");
                   if(d1==d2)
                   {  System.out.println(number+"是回文数");
                   }
                  else
                   {  System.out.println(number+"不是回文数");
                   }
                }
                else if(d1!=0)
                {  System.out.println(number+"是1位数");
                   System.out.println(number+"是回文数");
                }
           }
      else 
      {  System.out.printf("\n%d不在1至99999之间",number);
      }
   }
}