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POJ - 2632 - Crashing Robots = 模拟

http://poj.org/problem?id=2632

模拟起来还是蛮麻烦的。

不过总比一堆函数好。

#include<algorithm>
#include<cmath>
#include<cstdio>
#include<cstring>
#include<iostream>
#include<map>
#include<set>
#include<stack>
#include<string>
#include<queue>
#include<vector>
using namespace std;
typedef long long ll;

int dx[] = {-1, 0, +1, 0, -1};
int dy[] = {-1, +1, 0, -1, 0};

struct _1Nd {
    int id;
    int dir;
    _1Nd() {
        id = 0;
        dir = 0;
    }
} _1nd[105][105];

int a, b;
bool out;

int rx[105], ry[105];

void show() {
    for(int i = 1; i <= a; ++i) {

        for(int j = 1; j <= b; ++j) {
            printf("%d", _1nd[i][j].dir);
        }
        printf("\n");
    }
    printf("---\n");
}


void Move(int id, int w) {
    if(out == 1)
        return;
    while(w--) {
        //printf("w=%d\n",w);
        int i = rx[id], j = ry[id];
        int di = dx[_1nd[i][j].dir];
        int dj = dy[_1nd[i][j].dir];
        if(i + di < 1 || j + dj < 1 || i + di > a || j + dj > b) {
            out = 1;
            printf("Robot %d crashes into the wall\n", _1nd[i][j].id);
            return;
        } else {
            if(_1nd[i + di][j + dj].id) {
                out = 1;
                printf("Robot %d crashes into robot %d\n", _1nd[i][j].id, _1nd[i + di][j + dj].id);
                return;
            } else {
                _1nd[i + di][j + dj] = _1nd[i][j];
                _1nd[i][j] = _1nd[0][0];
            }
        }
        rx[id] += di;
        ry[id] += dj;
        //show();
    }
}

void Rotate(int id, int w, int d) {
    if(out == 1)
        return;
    int i = rx[id], j = ry[id];
    w %= 4;
    while(w--) {
        _1nd[i][j].dir += d;
        if(_1nd[i][j].dir == 5)
            _1nd[i][j].dir = 1;
        if(_1nd[i][j].dir == 0)
            _1nd[i][j].dir = 4;
        //show();
    }
}

int main() {
#ifdef Yinku
    freopen("Yinku.in", "r", stdin);
#endif // Yinku
    int t;
    scanf("%d", &t);
    while(t--) {
        out = 0;
        scanf("%d%d", &b, &a);
        for(int i = 1; i <= a; ++i) {
            for(int j = 1; j <= b; ++j)
                _1nd[i][j] = _1nd[0][0];
        }
        int n, m;
        scanf("%d%d", &n, &m);
        for(int i = 1; i <= n; ++i) {
            scanf("%d%d", &ry[i], &rx[i]);
            rx[i] = a - rx[i] + 1;
            _1nd[rx[i]][ry[i]].id = i;
            char dir[2];
            scanf("%s", dir);
            if(dir[0] == 'E')
                _1nd[rx[i]][ry[i]].dir = 1;
            else if(dir[0] == 'S')
                _1nd[rx[i]][ry[i]].dir = 2;
            else if(dir[0] == 'W')
                _1nd[rx[i]][ry[i]].dir = 3;
            else
                _1nd[rx[i]][ry[i]].dir = 4;
        }
        //show();
        while(m--) {
            int id, w;
            char op[2];
            scanf("%d%s%d", &id, op, &w);
            if(op[0] == 'F') {
                Move(id, w);
            } else if(op[0] == 'L') {
                Rotate(id, w, -1);
            } else {
                Rotate(id, w, 1);
            }
        }
        if(out == 0)
            puts("OK");
    }
}
posted @ 2019-10-22 13:11  Inko  阅读(84)  评论(0编辑  收藏  举报