os模块——获取上层目录
import os# 获取当前目录 print(os.getcwd()) print(os.path.abspath(os.path.dirname(__file__))) print(os.path.abspath('.')) # 获取当前文件 print(os.path.abspath(__file__)) # 获取上级目录 print(os.path.abspath(os.path.dirname(os.getcwd()))) print(os.path.abspath(os.path.dirname(os.path.dirname(__file__)))) print(os.path.abspath(os.path.join(os.getcwd(), ".."))) # 获取上上级目录 print(os.path.abspath(os.path.join(os.getcwd(), "../.."))) os.getcwd() # Return a unicode string representing the current working directory os.path.dirname() # Returns the directory component of a pathname os.path.abspath() # Return the absolute version of a path
本文来自博客园,作者:{IceSparks},转载请注明原文链接:https://www.cnblogs.com/IceSparks/p/16445459.html

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