将成绩变为等级

program yingfa;
var
  g : integer;
begin
  write('please input a number of grade: ');
  readln(g);
  if (g < 0) or (g > 100) then
    writeln(' input error. :( ...')
  else
    case g of
      90..100: writeln('A');
      80..89 : writeln('B');
      60..79 : writeln('C')
    else writeln('D');
    end;
end.

====================================== OR ======================================

program yingfa;
var
  g : integer;
begin
  write('please input a number of grade: ');
  readln(g);
  if (g < 0) or (g > 100) then
    writeln(' input error. :( ...')
  else
    if g >= 90 then writeln('A')
    else if g >= 80 then writeln('B')
    else if g >= 60 then writeln('C')
    else writeln('D');
end.
posted @ 2010-01-01 18:27  SmartIOI  阅读(159)  评论(0)    收藏  举报
本站采用CC授权如需转载、引用文章,请务必附上作者及来源处。 Creative Commons License