【日常水题-bfs】Red and Black

 Poj 1979 Red and Black

  题目大意:从@开始出发,“.”可走,“#”不可走,给出多组数据,“0 0”为结尾,求每组数据可以走到多少点(起点也算一个点)。

  夏令营讲课的时候它的评价:

 

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<iostream>
 4 using namespace std;
 5 const int sz = 25;
 6 char plat[sz][sz];
 7 int n, m, ans = 0;
 8 int q[sz*sz][3];
 9 bool book[sz][sz];
10 int dx[8] = {-1,0,1,0}, dy[8] = {0,1,0,-1};
11 int bfs(int x,int y) {
12     int head = 1, tail = 1, mx, my;
13     q[head][1] = x, q[head][2] = y;
14     book[x][y] = 1;
15     while(head<=tail) {
16         for(int i = 0; i < 4; i++) {
17             mx = q[head][1] + dx[i];
18             my = q[head][2] + dy[i];
19             if(mx>=1&&my>=1&&mx<=m&&my<=n&&(plat[mx][my]!='#')&&(!book[mx][my])) {
20                 tail++;
21                 q[tail][1] = mx;
22                 q[tail][2] = my;
23                 book[mx][my] = 1;
24             }
25         }
26         head++;
27     }
28     ans = tail;
29     return ans;
30 }
31 int main() {
32     while(1) {
33         memset(book,0,sizeof(book));
34         scanf("%d%d",&n,&m);
35         if(n==0&&m==0) break;
36         for(int i = 1; i <= m; i++) {
37                 scanf("%s",plat[i]+1);
38         }
39         for(int i = 1; i <= m; i++) {
40             for(int j = 1; j <= n; j++)
41             {
42             //    printf("%c",s[i][j]);    
43                 if(plat[i][j]=='@') {
44                     printf("%d\n",bfs(i,j));
45                     break;
46                 }
47             }
48         }
49     }
50     return 0;
51 }

准备刷刷夏令营yhy讲课的搜索专题qwq

这是第一个stO Orz

posted @ 2018-09-26 14:51  _Hwjia  阅读(165)  评论(0)    收藏  举报
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