//求解装载问题
#include<stdio.h>
#define MAXN 20
int n,W;
int maxw;
int x[MAXN];
int minm = 32767;
void disp(int n){ //当x[i]等于1时,说明选择该集装箱,输出
int i;
printf("选取的集装箱:\n");
for(i=1;i<=n;i++)
if(x[i] == 1)
printf("选取第%d个集装箱\n",i);
printf("总重量 = %d\n",maxw);
}
void Loading(int w[],int tw,int m,int op[],int i){ //考虑第i个集装箱
int j;
if(i>n){ //tw:在考虑第i个集装箱时装入的总重量 op[i]第i个集装箱的装载解向量
if(tw <= W && (tw > maxw || (tw == maxw && m < minm))){
maxw = tw; //
minm = m; //
for(j = 1;j<= n;j++)
x[j] = op[j];
}
}
else{
op[i] = 1;
if(tw + w[i] <= W) //左剪枝,装载满足条件的集装箱
Loading(w,tw+w[i],m+1,op,i+1);
op[i] = 0;
if(m <= 2) //右剪枝,至少选择3个集装箱
Loading(w,tw,m,op,i+1);
}
}
int main(){
int w[] = {0,5,2,6,4,3};
int op[MAXN]; //存放临时解
n = 5,W = 10;
Loading(w,0,0,op,1);
disp(n);
}