实验1

#include <stdio.h>
int main() 
{
    printf(" O \n");
    printf("<H>\n");
    printf("I I\n");
    
    printf(" O \n");
    printf("<H>\n");
    printf("I I\n");
    return 0;
}

#include <stdio.h>
int main()
{
printf(" O     O \n");
printf("<H>   <H>\n");
printf("I I   I I\n");
return 0;
}

#include <stdio.h>
int main()
{
double a, b, c;
scanf("%lf%lf%lf", &a, &b, &c);
if(a + b > c && a + c > b && b + c > a)
printf("能构成三角形\n");
else
printf("不能构成三角形\n");
return 0;
}

#include <stdio.h>

int main() {
    char ans1, ans2;

    printf("每次课前认真预习、课后及时复习了没？（输入y或Y表示有，输入n或N表示没有）: ");
    ans1 = getchar();

    getchar();//清空缓冲区 

    printf("\n动手敲代码实践了没？（输入y或Y表示敲了，输入n或N表示未有敲）: ");
    ans2 = getchar();

    // 判断两次回答是否均为小写或大写（即同为'y'/'Y'或同为'n'/'N'）
    if ((ans1 == 'y' && ans2 == 'y') , (ans1 == 'Y' && ans2 == 'Y') , 
        (ans1 == 'n' && ans2 == 'n') , (ans1 == 'N' && ans2 == 'N')) 
        printf("\n罗马不是一天建成的，继续保持哦:>\n");
        else 
        printf("\n罗马不是一天毁灭的，我们来建设吧\n");

    return 0;
}

#include<stdio.h>
int main()
{
double x, y;
char c1, c2, c3;
int a1, a2, a3;
scanf("%d%d%d", &a1, &a2, &a3);
printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3);
scanf(" %c %c %c", &c1, &c2, &c3);
printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
scanf("%lf,%lf", &x, &y);
printf("x = %f, y = %lf\n", x, y);
return 0;
}

#include <stdio.h>
#include <math.h>

int main() {
    int year;
    double seconds = 1e9;
    double seconds_per_year = 60 * 60 * 24 * 365;
    year = (int)round(seconds / seconds_per_year);
    printf("10亿秒约等于%d年\n", year);
    return 0;
}

#include <stdio.h>
#include <math.h>
int main()
{
double x, ans;
while(scanf("%lf", &x) != EOF)
{
ans = pow(x, 365);
printf("%.2f的365次方: %.2f\n", x, ans);
printf("\n");
}
return 0;
}

#include <stdio.h>
int main()
{
    double C, F;
    while(scanf("%lf",&C) != EOF)
    {
    F = (9.0/5.0) * C + 32;
    printf("%.2f摄氏度 = %.2f华氏度\n", C, F);
    printf("\n");
    }
    return 0;
}

#include <stdio.h>
#include <math.h>

int main() {
    double a, b, c;
    
    while (scanf("%lf %lf %lf", &a, &b, &c) == 3) {
        double s = (a + b + c) / 2;
        double area = sqrt(s * (s - a) * (s - b) * (s - c));
        printf("a=%.3f, b=%.3f, c=%.3f, area=%.3f\n", a, b, c, area);
    }
    
    return 0;
}