实验06

Posted on 2022-06-14 11:05  Hi,海  阅读(15)  评论(1编辑  收藏  举报
#include <stdio.h>#include <stdlib.h>
#define N 4

int main()
{
    int x[N] = {1, 9, 8, 4};
    int i;
    int *p;
    
    for(i=0; i<N; ++i)
        printf("%d", x[i]);
    printf("\n");
    
    for(p=x; p<x+N; ++p)
        printf("%d", *p);
    printf("\n"); 
    
    p = x;
    for(i=0; i<N; ++i)
        printf("%d", *(p+i));
    printf("\n");

    p = x;
    for(i=0; i<N; ++i)
        printf("%d", p[i]);
    printf("\n");
    
    system("pause");

}

 

 

 
#include <stdio.h>
#include <stdlib.h>
#define N 4

int main()
{
    char x[N] = {'1', '9', '8', '4'};
    int i;
    char *p;
    
    for(i=0; i<N; ++i)
        printf("%c", x[i]);
    printf("\n");
    
    for(p=x; p<x+N; ++p)
        printf("%c", *p);
    printf("\n"); 
    
    p = x;
    for(i=0; i<N; ++i)
        printf("%c", *(p+i));
    printf("\n");

    p = x;
    for(i=0; i<N; ++i)
        printf("%c", p[i]);
    printf("\n");
        system("pause");
    return 0;
}

 


 


2004


2001


int型指针变量占四个字节的内存单元


char型指针变量占一个字节的内存单元

 
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int x[2][4] = { {1,9,8,4}, {2,0,2,2}} ;
    int i, j;
    int *p;             
    int (*q)[4];    
    for(i=0; i<2; ++i)
    {
        for(j=0; j<4; ++j)
            printf("%d", x[i][j]);
        printf("\n");
     } 
    

    for(p = &x[0][0], i = 0; p < &x[0][0] + 8; ++p, ++i)
    {
        printf("%d", *p);
        if( (i+1)%4 == 0)
            printf("\n");
    }
    
    
    for(q=x; q<x+2; ++q)
    {
        for(j=0; j<4; ++j)
            printf("%d", *(*q+j));
        printf("\n");
    }


    system("pause");
}

 

 


#include <stdio.h>
#include <stdlib.h>
int main()
{
    char x[2][4] = { {'1', '9', '8', '4'}, {'2', '0', '2', '2'} };
    int i, j;
    char *p;        
    char (*q)[4];     
    
    
    for(i=0; i<2; ++i)
    {
        for(j=0; j<4; ++j)
            printf("%c", x[i][j]);
        printf("\n");
     } 
    

    for(p = &x[0][0], i = 0; p < &x[0][0] + 8; ++p, ++i)
    {
        printf("%c", *p);
        if( (i+1)%4 == 0)
            printf("\n");
    }
    
    for(q=x; q<x+2; ++q)
    {
        for(j=0; j<4; ++j)
            printf("%c", *(*q+j));
        printf("\n");
    }
    

    system("pause");
}

 


 

2004  2016

2001   2004

 

p指向的是二维数组元素的指针变量

q是指向一维数组的指针变量


#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>
#define N 80
int main()
{
char s1[] = "C, I love u.";
char s2[] = "C, I hate u.";
char tmp[N];
printf("sizeof(s1) vs. strlen(s1): \n");
printf("sizeof(s1) = %d\n", sizeof(s1));
printf("strlen(s1) = %d\n", strlen(s1));
printf("\nbefore swap: \n");
printf("s1: %s\n", s1);
printf("s2: %s\n", s2);
printf("\nswapping...\n");
strcpy(tmp, s1);
strcpy(s1, s2);
strcpy(s2, tmp);
printf("\nafter swap: \n");
printf("s1; %s\n", s1);
printf("s2: %s\n", s2);

return 0;


}

 

 


#include<stdio.h>
#include<string.h>
#define N 5
int check_id(char* str);
int main()
{
char* pid[N] = {
"31010120000721656X",
"330106199609203301",
"53010220051126571",
"510104199211197977",
"53010220051126133Y" };
int i;
for (i = 0; i < N; i++)
if (check_id(pid[i]))
printf("%s\tTrue\n", pid[i]);
else
printf("%s\tFalse\n", pid[i]);
return 0;
}
int check_id(char* str)
{
int i;
if (strlen(str) != 18)
return 0;
for (i = 0; i < 18; i++)
{
if ((str[i] >= '0' && str[i] <= '9') || str[i] == 'X')
continue;
else
return 0;
}
return 1;


 

 

 


实验3.1:1.大小是13;计算的是数组s1的大小;统计的是数组s1中的有效字符;


                                2.不能;


                                3.交换了。


                   实验3.2:1.存放的是字符串的首地址;计算的是地址变量s1所占的字节数;统计的是所有有效字符的个数;


                                 2.可以;


                                 3.交换的是地址;在内存存储单元中没有交换。


 
 
#include<stdio.h>
#include<string.h>
#define N 5
int check_id(char* str);
int main()
{
    char* pid[N] = {
        "31010120000721656X",
        "330106199609203301",
        "53010220051126571",
        "510104199211197977",
        "53010220051126133Y" };
    int i;
    for (i = 0; i < N; i++)
        if (check_id(pid[i]))
            printf("%s\tTrue\n", pid[i]);
        else
            printf("%s\tFalse\n", pid[i]);
    return 0;
}
int check_id(char* str)
{
    int i;
    if (strlen(str) != 18)
        return 0;
    for (i = 0; i < 18; i++)
    {
        if ((str[i] >= '0' && str[i] <= '9') || str[i] == 'X')
            continue;
        else
            return 0;
    }
    return 1;
}

 


 


#include<stdio.h>
#include<string.h>
#define N 80
int is_palindrome(char* s);
int main()
{
    char str[N];
    int flag;
    printf("Enter a string:\n");
    gets_s(str);
    flag = is_palindrome(str);
    if (flag)
        printf("YES\n");
    else
        printf("NO\n");
    return 0;
}
int is_palindrome(char* s)
{
    int i,j;
    j = strlen(s);
    for (i = 0;s[i]!='\0'; i++)
    {
        if (s[i] == s[j - i-1])
            continue;
        else
            return 0;
    }
    return 1;
}

 


 


#include<stdio.h>
#define N 80
void encoder(char* s);
void decoder(char* s);
int main()
{
    char words[N];
    printf("输入英文文本: ");
    gets_s(words);

    printf("编码后的英文文本: ");
    encoder(words);
    printf("%s\n", words);

    printf("对编码后的英文文本解码: ");
    decoder(words);
    printf("%s\n", words);

    return 0;
}
void encoder(char* s)
{
    int i,j=0;
    for (i = 0; s[i] != '\0'; i++)
        j++;
    for (i = 0; i < j; i++)
    {
        if ((s[i] >= 'a' && s[i] < 'z') || (s[i] >= 'A' && s[i] < 'Z'))
            s[i] = s[i] + 1;
        else if ((s[i] == 'z') || (s[i] == 'Z'))
            s[i] = s[i] - 25;
    }
}
void decoder(char* s)
{
    int i, j = 0;
    for (i = 0; s[i] != '\0'; i++)
        j++;
    for (i = 0; i < j; i++)
    {
        if ((s[i] > 'a' && s[i] <= 'z') || (s[i] > 'A' && s[i] <= 'Z'))
            s[i] = s[i] - 1;
        else if ((s[i] == 'a') || (s[i] == 'A'))
            s[i] = s[i] + 25;
    }
}

 


 

 

 


 

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