Uva 12502 - Three Families

你为何这么叼！

Three Families 

Time limit: 1.000 seconds 

 

Three families share a garden. They usually clean the garden together at the end of each week, but last week, family C was on holiday, so family A spent 5 hours, family B spent 4 hours and had everything done. After coming back, family C is willing to pay $90 to the other two families. How much should family A get? You may assume both families were cleaning at the same speed.

$90/(5+4)*5=$50? No no no. Think hard. The correct answer is $60. When you figured out why, answer the following question: If family A and B spent x and y hours respectively, and family C paid $z, how much should family A get? It is guaranteed that both families should get non-negative integer dollars.

WARNING: Try to avoid floating-point numbers. If you really need to, be careful!

Input 

The first line contains an integer T (T100), the number of test cases. Each test case contains three integers x, y, z (1x, y10, 1z1000).

Output 

For each test case, print an integer, representing the amount of dollars that family A should get.

Sample Input 

2
5 4 90
8 4 123

Sample Output 

60
123

 

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Problemsetter: Rujia Liu, Special Thanks: Feng Chen, Md. Mahbubul Hasann, Youzhi Bao

 

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
int n,m,k;
int main(){
    int t;
    scanf("%d",&t);
    while(t--){
        scanf("%d%d%d",&n,&m,&k);
        printf("%d\n",k*(2*n-m)/((n+m)));
    }
    return 0;
}