关于 Maritozzo 问题的思考

来源于ac contest 219 B

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Time Limit: 2 sec / Memory Limit: 1024 MB

Score : 200200 points

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Problem Statement

You are given three strings S_1, S_2, S_3S1​,S2​,S3​ consisting of lowercase English letters, and a string TT consisting of 1, 2, 3.

Concatenate the three strings according to the characters in TT and print the resulting string. Formally, conform to the following instructions.

• For each integer ii such that 1 \leq i \leq |T|1≤i≤∣T∣, let the string s_isi​ be defined as follows:
  • S_1S1​, if the ii-th character of TT is 1;
  • S_2S2​, if the ii-th character of TT is 2;
  • S_3S3​, if the ii-th character of TT is 3.
• Concatenate the strings s_1, s_2, \dots, s_{|T|}s1​,s2​,…,s∣T∣​ in this order and print the resulting string.

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Constraints

• 1 \leq |S_1|, |S_2|, |S_3| \leq 101≤∣S1​∣,∣S2​∣,∣S3​∣≤10
• 1 \leq |T| \leq 10001≤∣T∣≤1000
• S_1S1​, S_2S2​, and S_3S3​ consist of lowercase English letters.
• TT consists of 1, 2, and 3.

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Input

Input is given from Standard Input in the following format:S_1S1​

S_2S2​
S_3S3​
TT

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Output

Print the answer.

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Sample Input 1 

mari
to
zzo
1321
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Sample Output 1 

marizzotomari

We have s_1 =s1​= mari, s_2 =s2​= zzo, s_3 =s3​= to, s_4 =s4​= mari. Concatenate these and print the resulting string:

 marizzotomari.

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Sample Input 2 

abra
cad
abra
123

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Sample Output 2 

abracadabra

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Sample Input 3 

a
b
c
1

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Sample Output 3 

a
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AC

#include <bits/stdc++.h>
using namespace std;
int main(){
    vector<string> s(4);
    for (int i = 1; i <= 3;i++)
        cin >> s.at(i);
    string t;
    cin >> t;
    for (auto i = 0; i < t.length();i++){
        int j = t.at(i) - '0';
        cout << s.at(j);
    }
    cout << endl;
}

 

对于这题，我i自己写的很是复杂。

结果呢？WA/TLE

在此就不展示自己的繁冗代码了。

这么简单的方法当然是借鉴过来的啦 <：

有个地方不是很清楚，

在于那个 at

不知道是不是 C++ 的特殊方法

我的 VScode 告诉我那是重载函数

如果可以这么使用的话

与 C 的 sprintf 大为相似

实现了 数组 与 字符串之间的转换

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希望有大佬出来指点一下，

鄙人必将感激不尽！