pat 1144 The Missing Number(20 分)

1144 The Missing Number(20 分)

Given N integers, you are supposed to find the smallest positive integer that is NOT in the given list.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (105​​). Then N integers are given in the next line, separated by spaces. All the numbers are in the range of int.

Output Specification:

Print in a line the smallest positive integer that is missing from the input list.

Sample Input:

10
5 -25 9 6 1 3 4 2 5 17

Sample Output:

7
 
 1 #include <map>
 2 #include <set>
 3 #include <queue>
 4 #include <cmath>
 5 #include <stack>
 6 #include <vector>
 7 #include <string>
 8 #include <cstdio>
 9 #include <cstring>
10 #include <climits>
11 #include <iostream>
12 #include <algorithm>
13 #define wzf ((1 + sqrt(5.0)) / 2.0)
14 #define INF 0x3f3f3f3f
15 #define LL long long
16 using namespace std;
17 
18 const int MAXN = 1e6 + 10;
19 
20 int n, A[MAXN] = {0}, a;
21 
22 int main()
23 {
24     scanf("%d", &n);
25     for (int i = 0; i < n; ++ i)
26     {
27         scanf("%d", &a);
28         if (a <= 0 || a > MAXN) continue;
29         A[a] = 1;
30     }
31     for (int i = 1; ; ++ i)
32         if (A[i] == 0)
33         {
34             printf("%d\n", i);
35             break;
36         }
37     return 0;
38 }

 

posted @ 2018-09-03 17:21  GetcharZp  阅读(226)  评论(0编辑  收藏  举报