//编写一个函数,传入一个整数,将数字反转,检查数字是不是数字的2倍 果是则返回true,否则返回false

思路:

比如 n =1234;

那么如何获取4,应该 n%10;

那么如何获取3,获取3之前应该删除4,所以n/10;

//40 +3 =43
//43*10 = 430>430+2(432)>432*10(4320)+1
r=0  
怎么获取40:r *10 +d 
看代码:
 1 public class test2 {
 2     public static void main(String[] args) {
 3         int r = 0;
 4         int input =1234;
 5         int n =input %10;
 6         input = input / 10;
 7         r= r *10 +n;
 8         System.out.println(r);
 9         System.out.println(input);
10         n = input %10;
11         input = input / 10;
12         r =r *10 +n;
13         System.out.println(r);
14         System.out.println(input);
15         n = input %10;
16         input = input /10;
17         System.out.println(n);
18         System.out.println(input);
19     }
20 }

完整代码:

     public static void number_1( int number){
         int r =0;
         int o = number;
         while (number!=0){
            int n =number %10;
            number =number /10;
            r = r *10 + n;
         }
         boolean is = (r ==0 *2);
         System.out.println(is);
     }

　　

posted @ 2024-06-05 22:37  GOZO  阅读(10)  评论(0)    收藏  举报