hdu 1196 Lowest Bit

题目连接

http://acm.hdu.edu.cn/showproblem.php?pid=1196

Lowest Bit

Description

Given an positive integer $A (1 \leq A \leq 100)$, output the lowest bit of $A.$

For example, given $A = 26$, we can write $A$ in binary form as $11010$, so the lowest bit of $A$ is $10$, so the output should be $2$.

Another example goes like this: given $A = 88$, we can write $A$ in binary form as $1011000$, so the lowest bit of $A$ is $1000$, so the output should be $8$.

Input

Each line of input contains only an integer $A (1 \leq A \leq 100).$ $A$ line containing $"0"$ indicates the end of input, and this line is not a part of the input data.

Output

For each A in the input, output a line containing only its lowest bit.

Sample Input

26
88
0

Sample Output

2
8

 1 #include<algorithm>
 2 #include<iostream>
 3 #include<cstdlib>
 4 #include<cstring>
 5 #include<cstdio>
 6 #include<vector>
 7 #include<map>
 8 #include<set>
 9 using std::set;
10 using std::map;
11 using std::cin;
12 using std::cout;
13 using std::endl;
14 using std::find;
15 using std::sort;
16 using std::pair;
17 using std::vector;
18 #define sz(c) (int)(c).size()
19 #define all(c) (c).begin(), (c).end()
20 #define iter(c) decltype((c).begin())
21 #define cls(arr,val) memset(arr,val,sizeof(arr))
22 #define cpresent(c, e) (find(all(c), (e)) != (c).end())
23 #define rep(i, n) for (int i = 0; i < (int)(n); i++)
24 #define tr(c, i) for (iter(c) i = (c).begin(); i != (c).end(); ++i)
25 #define pb(e) push_back(e)
26 #define mp(a, b) make_pair(a, b)
27 const int Max_N = 100010;
28 typedef unsigned long long ull;
29 int main() {
30 #ifdef LOCAL
31     freopen("in.txt", "r", stdin);
32     freopen("out.txt", "w+", stdout);
33 #endif
34     int n, ans;
35     while (~scanf("%d", &n) && n) {
36         ans = 1;
37         while (true) {
38             if (n & 1) break;
39             ans <<= 1;
40             n >>= 1;
41         }
42         printf("%d\n", ans);
43     }
44     return 0;
45 }
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posted @ 2015-06-22 22:43  GadyPu  阅读(207)  评论(0编辑  收藏  举报