bzoj 1012 [JSOI2008]最大数maxnumber

原题链接:http://www.lydsy.com/JudgeOnline/problem.php?id=1012 
线段树,单点更新。。

 1 #include<algorithm>
 2 #include<iostream>
 3 #include<cstdlib>
 4 #include<cstdio>
 5 #define lc root<<1
 6 #define rc root<<1|1
 7 using std::max;
 8 const int Max_N = 200010;
 9 const int INF = 0x3f3f3f3f;
10 int MOD;
11 struct Node { int val; };
12 struct SegTree {
13     Node seg[Max_N << 2];
14     inline void push_up(int root) {
15         seg[root].val = max(seg[lc].val, seg[rc].val);
16     }
17     inline void update(int root, int l, int r, int pos, int t) {
18         if (pos > r || pos < l) return;
19         if (pos <= l && pos >= r) {
20             seg[root].val += t;
21             return;
22         }
23         int mid = (l + r) >> 1;
24         update(lc, l, mid, pos, t);
25         update(rc, mid + 1, r, pos, t);
26         push_up(root);
27     }
28     inline int query(int root, int l, int r, int x, int y) {
29         if (x > r || y < l) return -INF;
30         if (x <= l && y >= r) return seg[root].val;
31         int mid = (l + r) >> 1;
32         int v1 = query(lc, l, mid, x, y);
33         int v2 = query(rc, mid + 1, r, x, y);
34         return max(v1, v2);
35     }
36 }seg;
37 int main() {
38 #ifdef LOCAL
39     freopen("in.txt", "r", stdin);
40     freopen("out.txt", "w+", stdout);
41 #endif
42     char ch;
43     int n, v, res, len = 0;
44     while (~scanf("%d %d", &n, &MOD)) {
45         res = 0;
46         for (int i = 0; i < n; i++) {
47             getchar();
48             scanf("%c %d", &ch, &v);
49             if (ch == 'A') ++len, seg.update(1, 1, n, len, (res + v) % MOD);
50             else printf("%d\n", res = seg.query(1, 1, n, len - v + 1, n));
51         }
52     }
53     return 0;
54 }
View Code

 

By: GadyPu 博客地址:http://www.cnblogs.com/GadyPu/ 转载请说明
posted @ 2015-05-24 21:53  GadyPu  阅读(117)  评论(0编辑  收藏  举报