hdu 2275 Kiki & Little Kiki 1

原题链接：http://acm.hdu.edu.cn/showproblem.php?pid=2275 
题意：n个操作 
Push 入容器 
Pop弹出一个 满足<=该数的最大的数（若没有输出No Element!） 
用两个堆模拟。

 1 #include<functional>
 2 #include<algorithm>
 3 #include<iostream>
 4 #include<string>
 5 #include<cstdlib>
 6 #include<cstring>
 7 #include<cstdio>
 8 #include<vector>
 9 #include<queue>
10 using std::vector;
11 using std::greater;
12 using std::priority_queue;
13 priority_queue<int> que1;
14 priority_queue<int, vector<int>, greater<int> >que2;
15 void solve(){
16     int v;
17     char buf[10];
18     scanf("%s %d", buf, &v);
19     if ('u' == buf[1]){
20         que2.push(v);
21     } else {
22         while(!que2.empty()){
23             int x = que2.top();
24             if (x <= v) que1.push(x), que2.pop();
25             else break;
26         }
27         if (que1.empty()) puts("No Element!");
28         else printf("%d\n", que1.top()), que1.pop();
29     }
30 }
31 int main(){
32 #ifdef LOCAL
33     freopen("in.txt", "r", stdin);
34     freopen("out.txt", "w+", stdout);
35 #endif
36     int n;
37     while (~scanf("%d", &n)){
38         while (n--) solve();
39         while (!que1.empty()) que1.pop();
40         while (!que2.empty()) que2.pop();
41         printf("\n");
42     }
43     return 0;
44 }
View Code

 

posted @ 2015-05-06 20:50  GadyPu  阅读(345)  评论(0)  编辑  收藏  举报