django使用ModelForm上传文件 

 1 class ModelFormUploadFile(models.Model):
 2     '''ModelForm测试上传文件'''
 3     name = models.FileField(upload_to=settings.MEDIA_ROOT)
 4 
 5     class Meta:
 6         db_table = 'cmdbmgr_modelformuploadfile'
 7         verbose_name = 'ModelForm测试文件上传'
 8         verbose_name_plural = verbose_name
 9 
10 
11 from django import forms
12 from django.views.generic import TemplateView
13 
14 class UploadFileForm(forms.ModelForm):
15     class Meta:
16         model = ModelFormUploadFile
17         fields = '__all__'
18 
19 class UploadFileView(TemplateView):
20     '''使用modelform方法上传文件'''
21     template_name = 'upload_file.html'
22     def get(self, request, *args, **kwargs):
23         '''渲染初始modelform'''
24         context = self.get_context_data()
25         context['form'] = UploadFileForm()
26         return self.render_to_response(context)
27 
28     def post(self, request):
29         '''提高'''
30         form = UploadFileForm(request.POST, request.FILES)
31         if form.is_valid():
32             form.save()
33             return HttpResponse('ok')
34         return HttpResponse('faild')

 

posted @ 2020-08-11 17:06  Fmaj-7  阅读(571)  评论(0)    收藏  举报