锁绑定多个条件condition

多线程之间按顺序调用，实现A->B->C，要求AA打印5次，BB打印10次，CC打印15此。循环10次。

代码：

public class ConditionDemo {
    public static void main(String[] args) {
        PrintStr printStr = new PrintStr();

        new Thread(()->{
            for (int i = 1; i <=10 ; i++) {
                printStr.print5();
            }
        },String.valueOf("t1")).start();

        new Thread(()->{
            for (int i = 1; i <=10 ; i++) {
                printStr.print10();
            }
        },String.valueOf("t2")).start();

        new Thread(()->{
            for (int i = 1; i <=10 ; i++) {
                printStr.print15();
            }
        },String.valueOf("t3")).start();
    }
}

class PrintStr{
    private int number=1;
    private Lock lock=new ReentrantLock();
    private Condition condition1=lock.newCondition();
    private Condition condition2=lock.newCondition();
    private Condition condition3=lock.newCondition();

    public void print5(){
        lock.lock();
        try{
            //判断
            while(number!=1){
                //当前线程阻塞
                condition1.await();
            }
            for (int i = 1; i <=5 ; i++) {
                System.out.println(Thread.currentThread().getName()+"\t"+i);
            }
            //操作
            number=2;
            //通知另一个线程执行
            condition2.signal();
        }catch (Exception e){
            e.printStackTrace();
        }finally {
            lock.unlock();
        }
    }

    public void print10(){
        lock.lock();
        try{
            while(number!=2){
                condition2.await();
            }
            for (int i = 1; i <=10 ; i++) {
                System.out.println(Thread.currentThread().getName()+"\t"+i);
            }
            number=3;
            condition3.signal();
        }catch (Exception e){
            e.printStackTrace();
        }finally {
            lock.unlock();
        }
    }

    public void print15(){
        lock.lock();
        try{
            while(number!=3){
                condition3.await();
            }
            for (int i = 1; i <=15 ; i++) {
                System.out.println(Thread.currentThread().getName()+"\t"+i);
            }
            number=1;
            condition1.signal();
        }catch (Exception e){
            e.printStackTrace();
        }finally {
            lock.unlock();
        }
    }
}

结果：