LeetCode94. Binary Tree Inorder Traversal
题意
给一棵树, 输出中序遍历
方法
- 递归
代码
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
void dfs(vector<int>& res, TreeNode* root)
{
if (root == nullptr) return;
dfs(res, root->left);
res.push_back(root->val);
dfs(res, root->right);
}
vector<int> inorderTraversal(TreeNode* root) {
vector<int> res;
dfs(res, root);
return res;
}
};