POJ 3630 Phone List [Trie]

判断是否有前缀...明显就是一个trie了...裸的不能再裸

注意用动态的trie额外分配内存的时候会TLE...所以就用静态的...

不过静态trie一开始还不太会用...不过后来感觉思路和静态邻接表感觉差不多...

#include <set>
#include <map>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <cstdio>
#include <string>
#include <vector>
#include <cassert>
#include <cstdlib>
#include <cstring>
#include <sstream>
#include <fstream>
#include <numeric>
#include <iomanip>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
//typedef long long LL;
//typedef __int64 LL;
//typedef long double DB;
//typedef unisigned __int64 LL;
//typedef unsigned long long ULL;
#define EPS  1e-8
#define MAXN 100005
#define MAXE 300000
#define INF  0x3f3f3f3f
#define PI   acos(-1.0)
#define MOD  99991
//#define MOD  99990001
//#define MOD  1000000007
#define max(a,b) 	((a)>(b)?(a):(b))
#define min(a,b) 	((a)<(b)?(a):(b))
#define max3(a,b,c) (max(max(a,b),c))
#define min3(a,b,c) (min(min(a,b),c))
#define mabs(a) 	((a<0)?(-a):a)
//#define L(t) 		(t << 1)  //Left son t*2
//#define R(t) 		(t << 1 | 1) //Right son t*2+1
//#define Mid(a,b) 	((a+b)>>1) //Get Mid
//#define lowbit(a) (a&-a) //Get Lowbit
//int gcd(int a,int b){return b?gcd(b,a%b):a;}
//int lcm(int a,int b){return a*b/gcd(a,b);}
//std::ios::sync_with_stdio(false);
struct  trie
{
	int next[10];
	bool vis;
}tree[MAXN];
struct  alpha
{
	int len ;
	char ch[11];
}str[MAXN];
int cnt,n,T,loc;
bool judge;
void insert(alpha s)
{
	int now = 1,len = s.len;
	for(int i  = 0 ; i < len ; i++)
	{
		int tmp = s.ch[i] - '0';
		if(tree[now].next[tmp] == -1)
		{
			tree[now].next[tmp] = loc;
			if(i == len-1)
				tree[loc].vis = true;
            else
                tree[loc].vis = false;
			for(int j = 0 ; j < 10 ; j++)
				tree[loc].next[j] = -1;
			now = loc;
			loc++;
		}else
		{
			now = tree[now].next[tmp];
			if(tree[now].vis || (i == len-1))
			{
				judge = true;
				return;
			}
		}
	}
}
int main()
{
//  freopen("in.txt","r",stdin);
//  freopen("out.txt","w",stdout);
	cin>>T;
	while(T--)
	{
	    tree[1].vis = false;
	    judge = false;
		loc = 2;
        for(int i = 0 ; i < 10 ; i++)
            tree[1].next[i] = -1;
		cin>>n;
		for(int i = 0 ; i < n ; i++)
		{
			scanf("%s",str[i].ch);
			str[i].len = strlen(str[i].ch);
		}
		for(int i = 0 ; i < n ; i++)
		{
			if(!judge)
				insert(str[i]);
			else
                break;
		}
		if(judge)
			cout<<"NO"<<endl;
		else
			cout<<"YES"<<endl;
	}
    return 0;
}


posted @ 2013-04-23 13:54  Felix_F  阅读(135)  评论(0)    收藏  举报