python练习测试三级菜单功能

三级菜单实现：输入上级菜单，显示下级，输入b返回上级菜单，输入e退出程序

 

#！/usr/bin/env python

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# -*-coding:utf-8-*-

#Author:Feng Zhang

menu_list = {"北京":{
                    "海淀":{
                           "中关村":("海龙","科贸"),
                           "保福寺":("恒兴","都市网景")
                          },
                    "昌平":{},
                    "朝阳":{},
                    "丰台":{}
                   },
            "河北":{
                    "衡水":{},
                    "石家庄":{},
                    "邢台":{}
                   },
            "河南":{
                    "郑州":{},
                    "驻马店":{}
                   }
            }
flag_exit = False
while not flag_exit:  #循环打印一级菜单，获取用户输入，然后打印用户选的菜单对应的子菜单
    for menu_1 in menu_list: #打印一级菜单
        print(menu_1)
    choice_1 = input("plase input your choice1(b 返回上一级，e 退出)>>>")  #获取用户输入
    if choice_1 in menu_list: #判断用户输入的菜单是否有效（有效：打印下级菜单，输入b退出程序，e退出程序
        while not flag_exit: #输入正确的一级菜单，打印一级菜单下面的子菜单
            for i in menu_list[choice_1]:#打印二级菜单
                print('\t',i)
            choice_2 = input("plase input your choice2(b 返回上一级，e 退出)>>>")#获取用户输入的二级菜单
            if choice_2 in menu_list[choice_1]:
                while not flag_exit:
                    for i in menu_list[choice_1][choice_2]:#打印三级菜单
                        print('\t\t',i)
                    choice_3 = input("plase input your choice3(b 返回上一级，e 退出)>>>")#获取三级输入
                    if choice_3 in menu_list[choice_1][choice_2]:
                        while not flag_exit:
                            for i in menu_list[choice_1][choice_2][choice_3]:#打印三级菜单对应的子菜单
                                print('\t\t\t',i)
                            choice_4 = input("The last level,press b return(b 返回上一级，e 退出)>>>")#输入b重新查看其他三级菜单对应的子菜单
                            if choice_4 == 'b':
                                break
                            elif choice_4 == 'e':
                                flag_exit = True
                            else:
                                print("无效的输入")
                    elif choice_3 == 'b':
                        break
                    elif choice_3 == 'e':
                        flag_exit = True
                    else:
                        print("your input is valide,plase input your choice3>>>")
            elif choice_2 == 'b':
                break
            elif choice_2 == 'e':
                flag_exit = True
            else:
                print("your input is valide,plase input your choice2>>>")
    elif choice_1 == 'b':
        break
    elif choice_1 == 'e':
        flag_exit = True
    else:
        print("your input is valide,plase input your choice1>>>")