实验四
#include<stdio.h> #define N 4 int main() { int a[N]={2,0,2,2}; char b[N]={'2','0','2','2'}; int i; printf("sizeof(int)=%d\n",sizeof(int)); printf("sizeof(char)=%d\n",sizeof(char)); printf("\n"); //输出数组a中每个元素的地址、值 for(i=0;i<N;++i) printf("%p:%d\n",&a[i],a[i]); printf("\n"); //输出数组b中每个元素的地址、值 for(i=0;i<N;++i) printf("%p:%c\n",&b[i],b[i]); printf("\n"); //输出数组名a和b对应的值 printf("a=%p\n",a); printf("b=%p\n",b); return 0; }

1.int连续存放,四个字节
2.char连续存放,一个字节
#include<stdio.h> #define N 2 #define M 3 int main() { int a[N][M]={{1,2,3},{4,5,6}}; char b[N][M]={{'1','2','3'},{'4','5','6'}}; int i,j; //输出二维数组a中每个元素的地址和值 for(i=0;i<N;++i) for(j=0;j<M;++j) printf("%p:%d\n",&a[i][j],a[i][j]); printf("\n"); //输出二维数组a中每个元素的地址和值 for(i=0;i<N;++i) for(j=0;j<M;++j) printf("%p:%c\n",&b[i][j],b[i][j]); return 0; }

1.int二维数组连续存放,每个元素4个字节
2.char二维数组连续存放,每个元素1个字节
#include<stdio.h> int days_of_year(int year,int month,int day);//函数声明 int main() { int year,month,day; int days; while(scanf("%d%d%d",&year,&month,&day)!=EOF)//按下Ctrl+Z终止 { days=days_of_year(year,month,day);//函数调用 printf("%4d-%02d-%02d是这一年的第%d天.\n\n",year,month,day,days); } return 0; } int days_of_year(int year,int month,int day) {int sum=0,i,a[]={0,31,28,31,30,31,30,31,31,30,31,30,31}; if(year % 400 == 0 || year % 100 != 0 && year % 4 == 0) {a[2]++;} for(i=1;i<month;i++) { sum+=a[i]; } sum+=day; return sum; } //函数定义 //补足函数days_of_year的定义 //xxx

#include<stdio.h> #define N 5 //函数声明 void input(int x[],int n); void output(int x[],int n); double average(int x[],int n); void sort(int x[],int n); int main() { int scores[N]; double ave; printf("录入%d个分数:\n",N); input(scores,N); printf("\n输出课程分数:\n"); output(scores,N); printf("\n课程分数处理:计算均分、排序...\n"); ave=average(scores,N); sort(scores,N); printf("\n输出课程均分:%.2f\n",ave); printf("\n输出课程分数(高->低):\n"); output(scores,N); return 0; } //函数定义 //输入n个整数保存到整型数组x中 void input(int x[],int n) { int i; for(i=0;i<n;++i) scanf("%d",&x[i]); } //输出整型数组x中n个元素 void output(int x[],int n) { int i; for(i=0;i<n;++i) printf("%d ",x[i]); printf("\n"); } double average(int x[],int n) { double sum=0; int i; for(i=0;i<n;i++) sum+=x[i]; return sum/n; } void sort(int a[],int n) { int i,j,index; int temp; int m; for(i = 0; i < n-1; i++){ index=i; for(j = i + 1;j < n; j++){ //寻找最小值 if(a[index]<a[j]) //a[i]若不是最小 index=j; //记录最小值下标 } if(index !=i) //最小值和第i个记录进行互换 { temp=a[i]; a[i]=a[index]; a[index]= temp; //a[i]的值赋给被交换的位置 } } } //计算整型数组x中n个元素均值,并返回 //补足函数average()实现 //××× //对整型数组x中的n个元素降序排序 //补足函数sort()实现 //××x

#include<stdio.h> #include<string.h> void dec2n(int x,int n);//函数声明 int main() { int x; printf("输入一个十进制整数:"); scanf("%d",&x); dec2n(x,2);//函数调用:把x转换成二进制输出 dec2n(x,8);//函数调用:把x转换成八进制输出 dec2n(x,16);//函数调用:把x转换成十六进制输出 return 0; } //函数定义 //功能:把十进制数x转换成n进制,打印输出 //补足函数实现 void dec2n(int x,int n) {char b[50]; memset(b,0,sizeof(b)); int i=0; while(x){ b[i]=x%n; if(b[i]>9){ b[i] += 'A'-10; }else{ b[i] +='0'; } x=x/n; i++; } while(i--){ printf("%c",b[i]); }printf("\n"); } //待补足
#include <stdio.h> #define N 100 int main() { int a[N][N] = {0}; int n; int i, j, k; printf("Enter n: "); while(scanf("%d", &n)!=EOF) { for (i = 0; i < n; i++) { for (j = i; j < n; j++) { a[i][j] = i + 1; a[j][i] = a[i][j]; } } for (i = 0; i < n; i++) { for (j = 0; j < n; j++) { printf("%2d ", a[i][j]); } printf("\n"); }printf("\nEnter n: "); } return 0; }

#include<stdio.h> #define N 80 int main() { char views1[N] = "hey,c,i hate u."; char views2[N] = "hey,c,i,love u."; int i; printf("original views:\n"); printf("views1:%s\n", views1); printf("views2:%s\n", views2); printf("\n"); for (i = 0; i < N; i++) { views1[20] = views1[i]; views1[i] = views2[i]; views2[i] = views1[20]; } printf("swapping...\n"); printf("views1:%s\n", views1); printf("views2:%s\n", views2); return 0; }

#include <stdio.h> #include <string.h> #define N 5 #define M 20 void bubble_sort(char str[][M], int n); //函数声明 int main() { char name[][M] = {"Bob", "Bi1l", "Joseph", "Tay1or", "George"}; int i; printf("输出初始名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); printf("\n排序中...\n"); bubble_sort(name, N); // 函数调用 printf("\n按字典序输出名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); return 0; } void bubble_sort(char str[][M], int n) { char *tmp; int i, j; for (i = 0; i < n; i++) { for (j = 0; j < n - 1 - i; j++) { if (strcmp(str[j], str[j + 1]) > 0) { *tmp = *str[j]; *str[j] = *str[j + 1]; *str[j + 1] = *tmp; } } } }

posted on 2022-05-08 21:54 FLWkingtgerrr 阅读(23) 评论(1) 收藏 举报

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