3n+1

#include<stdio.h>
int main()
{
    long long n;
    int c;
    while(scanf("%lld",&n)!=EOF){
        c=0;
        while(n!=1){
            if(n%2==0){
            n=n/2;c++;
            }
            else{
            n=3*n+1;c++;
            }
        }
    printf("%d\n",c);
    }
    return 0;
}

 

posted @ 2018-12-10 23:38  Estwind  阅读(358)  评论(0编辑  收藏  举报