第六周作业

import java.util.Scanner;
public class demo1 {
    public static void main(String[] args) {
        int[] a = new int[5];
        int i, j;
        int temp;
        Scanner input = new Scanner(System.in);
        System.out.println("请输入5个整数:");
        for (i = 0; i < 5; i++) {
            a[i] = input.nextInt();
        }
        for (i = 0; i < a.length - 1; i++) {
            for (j = 0; j < a.length - 1 - i; j++) {
                if (a[j] > a[j + 1]) {
                    temp = a[j];
                    a[j] = a[j + 1];
                    a[j + 1] = temp;
                }
            }
        }
        System.out.println("排序后:");
        for (i = 0; i < a.length; i++) {
            System.out.println(a[i] + "\t");
        }
    }
}

2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found"

import java.util.Scanner;
public class demo1 {
    public static void main(String[] args) {
        Scanner input=new Scanner(System.in);
        int n=0;
      int[] sz={34,22,35,67,45,66,12,33};
         System.out.println("输入一个数:");
         int a=input.nextInt();
          for (int i=0; i<sz.length;i++) {
                if (a==sz[i]){
                    System.out.println("该数组下标是:"+i);
                n=1;
                 }
             }
             if(n!=1){
                 System.out.println("not found");
    }       
  }
}

3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。

import java.util.Scanner;
public class demo1 {
    public static void main(String[] args) {
        double[][]arr={{1,2,3,4},{2,4,6,8},
                {3,6,9,2},{4,8,2,6},
                {5,0,5,0}};
        for(int i=0;i<arr.length;i++){
            System.out.println();
            for(int j=0;j<arr.length-1;j++){
                System.out.print(arr[i][j]+" ");
            }
        }    
    }
}

4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.

import java.util.Scanner;

public class demo1 {
    public static void main(String[] args) {
        int arr[][]={{2,6,7}, {56,45,9}, {8,45,6}, {99,78,45}};
        int max = arr[0][0];
        for (int i = 0; i < arr.length; i++) {
            for (int j = 0; j < arr[i].length; j++) {
                if (arr[i][j] > max) {
                    max = arr[i][j];
                }
            }
        }
        System.out.println("数组的最大值为" + max);
    }
}

 

posted @ 2020-04-15 12:25  EarlGary  阅读(143)  评论(0)    收藏  举报