第六周作业
import java.util.Scanner; public class demo1 { public static void main(String[] args) { int[] a = new int[5]; int i, j; int temp; Scanner input = new Scanner(System.in); System.out.println("请输入5个整数:"); for (i = 0; i < 5; i++) { a[i] = input.nextInt(); } for (i = 0; i < a.length - 1; i++) { for (j = 0; j < a.length - 1 - i; j++) { if (a[j] > a[j + 1]) { temp = a[j]; a[j] = a[j + 1]; a[j + 1] = temp; } } } System.out.println("排序后:"); for (i = 0; i < a.length; i++) { System.out.println(a[i] + "\t"); } } }
2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found"
import java.util.Scanner; public class demo1 { public static void main(String[] args) { Scanner input=new Scanner(System.in); int n=0; int[] sz={34,22,35,67,45,66,12,33}; System.out.println("输入一个数:"); int a=input.nextInt(); for (int i=0; i<sz.length;i++) { if (a==sz[i]){ System.out.println("该数组下标是:"+i); n=1; } } if(n!=1){ System.out.println("not found"); } } }
3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。
import java.util.Scanner; public class demo1 { public static void main(String[] args) { double[][]arr={{1,2,3,4},{2,4,6,8}, {3,6,9,2},{4,8,2,6}, {5,0,5,0}}; for(int i=0;i<arr.length;i++){ System.out.println(); for(int j=0;j<arr.length-1;j++){ System.out.print(arr[i][j]+" "); } } } }
4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.
import java.util.Scanner; public class demo1 { public static void main(String[] args) { int arr[][]={{2,6,7}, {56,45,9}, {8,45,6}, {99,78,45}}; int max = arr[0][0]; for (int i = 0; i < arr.length; i++) { for (int j = 0; j < arr[i].length; j++) { if (arr[i][j] > max) { max = arr[i][j]; } } } System.out.println("数组的最大值为" + max); } }
浙公网安备 33010602011771号