1、编写一个简单程序,要求数组长度为5,分别赋值10,20,30,40,50,在控制台输出该数组的值。(知识点:数组定义和创建、一维数组初始化)[必做题]?
package text;
public class test1 {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int[] a={10,20,30,40,50};
for(int i=0;i<a.length;i++){
System.out.println(a[i]);
}
}
}
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2、将一个字符数组的值(neusofteducation)拷贝到另一个字符数组中。(知识点:数组复制) [必做题]?
package text;
import java.util.Arrays;
public class test2 {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
char []x={'c','h','i','n','a'};
char []y=new char[10];
System.arraycopy(x,0,y,0,5);
System.out.println(Arrays.toString(y));
}
}
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3、给定一个有9个整数(1,6,2,3,9,4,5,7,8)的数组,先排序,然后输出排序后的数组的值。(知识点:Arrays.sort排序、冒泡排序)
package text;
public class test3 {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int[] a = { 1, 6, 2, 3, 9, 4, 5, 7, 8};
for (int i = 0; i < a.length - 1; i++) {
for (int j = 0; j < a.length - 1 - i; j++) {
if (a[j] > a[j + 1]) {
int temp = a[j];
a[j] = a[j + 1];
a[j + 1] = temp;
}
}
}
for (int i : a) {
System.out.println(i);
}
}
}
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4、 输出一个double型二维数组(长度分别为5、4,值自己设定)的值。(知识点:数组定义和创建、多维数组初始化、数组遍历)
package text;
public class test4 {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int [][]a=new int[5][4];
for (int i = 0; i < a.length; i++) {
for (int j = 0; j < a[i].length; j++) {
a[i][j]=i+j;
}
}
System.out.println("矩阵是");
for (int i = 0; i < a.length; i++) {
for (int j = 0; j < a[i].length; j++) {
System.out.print(a[i][j]+" ");
}
System.out.println();
}
}
}
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5、 在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标。(知识点:数组遍历、数组元素访问) [必做题]?
package text;
public class test5 {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int a[]={18,25,7,6,13,2,89,63};
int max=a[0],maxXB=0;
for(int i=1;i<a.length;i++){
if(a[i]>max)
max=a[i];
maxXB=i;
}
System.out.println("最大值为"+max+",下标为"+maxXB);
}
}
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6.将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问)
package text;
public class text6 {
public static void main(String[] args) {
// TODO Auto-generated method stub
int s[] ={1,3,5,7,9,11,13,15,17,19};
int t;
for (int i = 0,j=s.length-1;i<j; i++,j--) {
t=s[i];
s[i]=s[j];
s[j]=t;
}
for (int i = 0; i < s.length; i++) {
System.out.print(s[i]+" ");
}
System.out.println();
}
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7、将一个数组中的重复元素保留一个其他的清零。(知识点:数组遍历、数组元素访问)
package text;
public class text7{
public static void main(String[] args) {
// TODO Auto-generated method stub
int a[]={2,4,6,8,2,5,4,2};
for (int i = 0; i < a.length; i++) {
for (int j = 0; j < a.length; j++) {
if(a[i]==a[j]){
if(i!=j){
a[j]=0;
}
}
}
System.out.println(a[i]);
}
}
}
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8、给定一维数组{ -10,2,3,246,-100,0,5},计算出数组中的平均值、最大值、最小值。(知识点:数组遍历、数组元素访问)
package text;
public class text8 {
public static void main(String[] args) {
// TODO Auto-generated method stub
int a[]={-10,2,3,246,-100,0,5};
int sum=0;
int max=0;
int min=0;
double j=0;
for (int i = 0; i < a.length; i++) {
sum+=a[i];
if(max<a[i]){
max=a[i];
}
if(min>a[i]){
min=a[i];
}
j=i+1;
}
System.out.println("平均值是:"+sum/j);
System.out.println("最大值是:"+max);
System.out.println("最小值是:"+min);
}
}
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9、使用数组存放裴波那契数列的前20项 ,并输出 1 1 2 3 5 8 13 21
package test;
import java.util.Arrays;
import java.util.Scanner;
public class text9 {
public static void main(String[] args) {
// TODO 自动生成的方法存根
int num[] = new int[20];
num[0] = 1;
num[1] = 1;
System.out.println("斐波那契数列前20项的值如下:");
System.out.print(num[0]+" "+num[1]+" ");
for(int i = 2; i < 20; i++){
num[i] = num[i - 1] + num[i - 2];
System.out.print(num[i]+" ");
}
}
}
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10、生成一个长度为10的随机整数数组(每个数都是0-100之间),输出,排序后,再输出
package test;
import java.util.Arrays;
import java.util.Scanner;
public class text10 {
public static void main(String[] args) {
Scanner input= new Scanner(System.in);
int temp=0;
int[] a = new int[10];
for (int i = 0; i < 10; i++) {
a[i] = input.nextInt();
}
for (int i = 0; i < 10; i++) {
for (int j = i + 1; j < 10; j++) {
if (a[i] > a[j]) {
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
for (int i = 0; i < 10; i++) {
System.out.print(a[i] + " ");
}
}
}
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