pku 1080 Human Gene Functions LCS变形

http://poj.org/problem?id=1080

discuss 里面的解释已经很经典很明白了。http://poj.org/showmessage?message_id=74842

View Code
#include <cstdio>
#include <cstring>
#include <iostream>
#define maxn 107
using namespace std;
int f[5][5] =
{
    {5,-1,-2,-1,-3},
    {-1,5,-3,-2,-4},
    {-2,-3,5,-2,-2},
    {-1,-2,-2,5,-1},
    {-3,-4,-2,-1,0}
};
int dp[maxn][maxn];
char st1[maxn],st2[maxn];
char tmp[5] = {'A','C','G','T','-'};
int getnum(char s)
{
    for (int i = 0; i < 5; ++i)
    {
        if (s == tmp[i])
        return i;
    }
    return -1;
}
int main()
{
    //freopen("in.txt","r",stdin);
    int i,j,t,l1,l2;
    scanf("%d",&t);
    while (t--)
    {
        scanf("%d%s",&l1,st1 + 1);
       scanf("%d%s",&l2,st2  +1);
      /* char ch[2];
       scanf("%s",ch);

        printf("%d\n",getnum(ch[0]));*/
        dp[0][0] = 0;
        memset(dp,0,sizeof(dp));
        for (i = 1; i <= l1; ++i)
        {
            int pos = getnum(st1[i]);
            //printf("<<<<>>%d\n",pos);
            dp[i][0] = dp[i - 1][0] + f[pos][4];
        }
        for (i = 1; i <= l2; ++i)
        {
            int pos = getnum(st2[i]);
            //printf("||<<<<>>%d\n",pos);
            dp[0][i] = dp[0][i - 1] + f[4][pos];
        }
        for (i = 1; i <= l1; ++i)
        {
            for (j = 1; j <= l2; ++j)
            {
                int x = getnum(st1[i]);
                int y = getnum(st2[j]);
                if (st1[i] == st2[j])
                {

                    dp[i][j] = dp[i - 1][j - 1] + f[x][y];
                }
                else
                {
                    dp[i][j] = max(max(dp[i - 1][j] + f[x][4],dp[i][j -1] + f[4][y]),dp[i - 1][j - 1] + f[x][y]);
                }
            }
        }
        printf("%d\n",dp[l1][l2]);
    }
    return 0;
}
posted @ 2012-04-30 10:36  E_star  阅读(138)  评论(0)    收藏  举报