烟_火
人间烟火何不尝

将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。 

示例:

输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
    public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
        ListNode returnNode = new ListNode(0);
        Merge(l1, l2, returnNode);
        return returnNode.next;
    }
    public void Merge(ListNode l1, ListNode l2, ListNode returnNode)
    {
        if(l1 == null)
        {
            returnNode.next = l2;
            return;
        }
        else if(l2 == null)
        {
            returnNode.next = l1;
            return;
        }
        else
        {
            if(l1.val <= l2.val)
            {
                returnNode.next = l1;
                ListNode tmpNode = l1.next;
                ListNode tmpNode1 = returnNode.next;
                 Merge(tmpNode, l2, tmpNode1);
            }
            else
            {
                returnNode.next = l2;
                ListNode tmpNode = l2.next;
                ListNode tmpNode1 = returnNode.next;
                Merge(l1, tmpNode, tmpNode1);
            }
        }
    }
} 

今日一句:

  时间能治愈一切,请给时间一点时间。

posted on 2020-03-10 21:37  段流儿  阅读(93)  评论(0编辑  收藏  举报