Leetcode 111. Minimum Depth of Binary Tree

111. Minimum Depth of Binary Tree

  • Total Accepted: 114343
  • Total Submissions:368035
  • Difficulty: Easy

 

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

 

思路:理解题意。

1. 左右子树如果有空,根的深度=非空的子树深度+1

2. 左右子树都不为空,根的深度=min(左子树深度,右子树深度)+1

 

代码:

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     int minDepth(TreeNode* root) {
13         if(root==NULL){
14             return 0;
15         }
16         int left=minDepth(root->left),right=minDepth(root->right);
17         return (!left||!right)?left+right+1:min(left,right)+1;
18     }
19 };

 

posted @ 2016-07-09 09:45  Deribs4  阅读(143)  评论(0编辑  收藏  举报