USACO Complete Search

 

Complete Search

The Idea（思想：）

Solving a problem using complete search is based on the ``Keep It Simple, Stupid'' principle. The goal of solving contest problems is to write programs that work in the time allowed, whether or not there is a faster algorithm.

爆搜解决问题就是用“简单的，盲目的”原则。解决问题的目标是能使你写的程序在规定时间内处理完，而不管他是不是一个高效的算法。

Complete search exploits the brute force, straight-forward, try-them-all method of finding the answer. This method should almost always be the first algorithm/solution you consider. If this works within time and space constraints, then do it: it's easy to code and usually easy to debug. This means you'll have more time to work on all the hard problems, where brute force doesn't work quickly enough.

爆搜是相当暴力，直接，他们用枚举来找到答案。这个方法应该是你第一时间想到的。如果时空都允许的情况下，你就会AC；这种方法非常利于写代码和调试。这意味这你讲拥有更多的时间去思考难的题目，那些仅仅用爆搜不能解决的。

In the case of a problem with only fewer than a couple million possibilities, iterate through each one of them, and see if the answer works.

这个问题的答案可能仅有百万分之一的可能性，但它会逐一遍历，直到找到答案。

Careful, Careful

Sometimes, it's not obvious that you use this methodology.

有时这不是一个很明显能去爆搜的题目。

Problem: Party Lamps [IOI 98]

You are given N lamps and four switches. The first switch toggles all lamps, the second the even lamps, the third the odd lamps, and last switch toggles lamps 1, 4, 7, 10, ... .

Given the number of lamps, N, the number of button presses made (up to 10,000), and the state of some of the lamps (e.g., lamp 7 is off), output all the possible states the lamps could be in.

Naively, for each button press, you have to try 4 possibilities, for a total of 4¹⁰⁰⁰⁰(about 10⁶⁰²⁰ ), which means there's no way you could do complete search (this particular algorithm would exploit recursion).

Noticing that the order of the button presses does not matter gets this number down to about 10000⁴ (about 10¹⁶ ), still too big to completely search (but certainly closer by a factor of over 10⁶⁰⁰⁰ ).

However, pressing a button twice is the same as pressing the button no times, so all you really have to check is pressing each button either 0 or 1 times. That's only 2⁴ = 16 possibilities, surely a number of iterations solvable within the time limit.

Problem 3: The Clocks [IOI 94]

A group of nine clocks inhabits a 3 x 3 grid; each is set to 12:00, 3:00, 6:00, or 9:00. Your goal is to manipulate them all to read 12:00. Unfortunately, the only way you can manipulate the clocks is by one of nine different types of move, each one of which rotates a certain subset of the clocks 90 degrees clockwise.

Find the shortest sequence of moves which returns all the clocks to 12:00.

The ``obvious'' thing to do is a recursive solution, which checks to see if there is a solution of 1 move, 2 moves, etc. until it finds a solution. This would take 9^k time, where k is the number of moves. Since k might be fairly large, this is not going to run with reasonable time constraints.

显然可以进行递归求解，看看是否有1次，2次等等的解，知道找到一个解。这大概有9^k 次，k是改变方式的个数。因为k可能相当大，所以在可以接受的时间内不可能运行完。

Note that the order of the moves does not matter. This reduces the time down to k⁹ , which isn't enough of an improvement.

However, since doing each move 4 times is the same as doing it no times, you know that no move will be done more than 3 times. Thus, there are only 4⁹possibilities, which is only 262,072, which, given the rule of thumb for run-time of more than 10,000,000 operations in a second, should work in time. The brute-force solution, given this insight, is perfectly adequate.

//他们对每个题目进行可行性分析，直到找到一种方式，能使爆搜的可行域在百万数量级一下。

Sample Problems

Milking Cows [USACO 1996 Competition Round]

Given a cow milking schedule (Farmer A milks from time 300 to time 1000, Farmer B from 700 to 1200, etc.), calculate

• The longest time interval in which at least one cow was being milked
• The longest time interval in which no cow is being milked

Perfect Cows & Perfect Cow Cousins [USACO 1995 Final Round]

A perfect number is one in which the sum of the proper divisors add up to the number. For example, 28 = 1 + 2 + 4 + 7 + 14. A perfect pair is a pair of numbers such that the sum of the proper divisor of each one adds up to the other. There are, of course, longer perfect sets, such that the sum of the divisors of the first add up to the second, the second's divisors to the third, etc., until the sum of the last's proper divisors add up to the first number.

Each cow in Farmer John's ranch is assigned a serial number. from 1 to 32000. A perfect cow is one which has a perfect number as its serial. A group of cows is a set of perfect cow cousins if their serial numbers form a perfect set. Find all perfect cows and perfect cow cousins.