javascript中，break，continue和return false的用法

如题，结论：

break：打断并跳出当前循环。
continue:仅跳出当次循环。
return false:打断当前方法并返回值

实践程序如下：

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="format-detection" content="telephone=no,email=no,adress=no">
    <meta name="viewport" content="width=device-width,  initial-scale=1, maximum-scale=1, minimum-scale=1,  user-scalable=no">
    <meta name="apple-mobile-web-app-capable" content="yes">
    <meta name="apple-mobile-web-app-status-bar-style" content="black">
    <title>Title</title>
</head>
<body>
<script>
    window.onload=()=>{
      let arr = ["a","b","c","d","e","f","g"];
      const breakFn = ()=>{
        for(let i=0;i<arr.length;i++){
          if(arr[i]==="d"){
            break;
          }
          console.log(arr[i]);
        }
        console.log("我是breakFn for后面的")
      };
      const continueFn = ()=>{
        for(let i=0;i<arr.length;i++){
          if(arr[i]==="d"){
            continue;
          }
          console.log(arr[i]);
        }
        console.log("我是continueFn for后面的")
      };
      const returnFn = ()=>{
        for(let i=0;i<arr.length;i++){
          if(arr[i]==="d"){
            return false;
          }
          console.log(arr[i]);
        }
        console.log("我是returnFn for后面的")
      };
      breakFn();
      console.log("===============");
      continueFn();
      console.log("===============");
      returnFn();
    };
</script>
</body>
</html>
运行结果：

 

posted @ 2020-04-01 14:52  大萨特  阅读(488)  评论(0)    收藏  举报