把12341234转换成"一千两百三十四万一千两百三十四"的算法...

在CSDN上看到这个问题, 觉得有点意思就用C#写了这么个算法...
其实不是很复杂, 主要是要处理多种输入的情况.

输出的例子:
12341234
一千二百三十四万一千二百三十四
10001024
一千万一千零二十四
199998001
一亿九千九百九十九万八千零一

其实有的地方念"两"比"二"要舒服, 这个问题...这个算法就没考虑了..

算法代码如下:

using System;
using System.Collections.Generic;
using System.Text;

namespace NumberReader
{
    class Program
    {
        static void Main(string[] args)
        {
            while (true)
            {
                string number = Console.ReadLine();
                Console.WriteLine(GetChineseString(number));
            }
        }
       
        private static string GetChineseString(string number)
        {
            int[] numbers = GetNumberArray(number);
            int currentPower = numbers.Length;
            int lastNum = 0;
            StringBuilder sb = new StringBuilder();
            while (currentPower > 0)
            {
                int currentNum = numbers[numbers.Length - currentPower];
                if (currentNum == 0 && lastNum == 0)
                {
                    if (currentPower % 4 == 1)
                    {
                        sb.Remove(sb.Length - 1, 1);
                        sb.Append(GetPowerChar(currentPower));
                    }
                    currentPower--;
                    continue;
                }
                sb.Append(GetChineseChar(currentNum));
                if (currentNum != 0)
                {
                    sb.Append(GetPowerChar(currentPower));
                }
                lastNum = currentNum;
                currentPower--;
            }
            return sb.ToString();
        }

        private static string GetPowerChar(int currentPower)
        {
            int mod = currentPower % 4;
            switch (mod)
            {
                case 0:
                    return "千";
                case 3:
                    return "百";
                case 2:
                    return "十";
                case 1:
                    int modmod = currentPower % 8;
                    switch (modmod)
                    {
                        case 5:
                            return "万";
                        case 1:
                            if (currentPower != 1)
                            {
                                return "亿";
                            }
                            break;
                    }
                    break;
            }
            return string.Empty;
        }

        private static string GetChineseChar(int p)
        {
            switch (p)
            {
                case 0:
                    return "零";
                case 1:
                    return "一";
                case 2:
                    return "二";
                case 3:
                    return "三";
                case 4:
                    return "四";
                case 5:
                    return "五";
                case 6:
                    return "六";
                case 7:
                    return "七";
                case 8:
                    return "八";
                case 9:
                    return "九";
            }
            return string.Empty;
        }

        private static int[] GetNumberArray(string number)
        {
            int[] arr = new int[number.Length];
            for (int i = 0; i < arr.Length; i++)
            {
                arr[i] = (int)number[i] - 48;
            }
            return arr;
        }
    }
}