摘要:
方法一: public static int Sum(int m) { int sum = 0; bool bol = true; for (int i=1;i<=m;i++) { if (bol == true) { sum += i; } else { sum -= i; } bol = !bo 阅读全文
摘要:
//冒泡排序 public static int[] Bubbling(int[] s) { int a; for (int i = 0; i < s.Length-1; i++) { for (int j =i+ 1; j < s.Length; j++) { if (s[i] >s[j]) { 阅读全文