不同地图坐标系的转换
高德、谷歌地图用的是Gcj坐标系(火星坐标系)
百度地图用的百度坐标系
const A = 6378245.0
const PI = 3.1415926535897932384626
const EE = 0.00669342162296594323
const LON_BOUNDARY_MIN = 72.004
const LAT_BOUNDARY_MIN = 0.8293
const LON_BOUNDARY_MAX = 137.8347
const LAT_BOUNDARY_MAX = 55.8271
const X_PI = 3.14159265358979324 * 3000.0 / 180.0
// 百度转wgs84
export function baidu09ToWgs84(lat, lon){
let info = bd09tToGcj02(lat,lon)
info = gcj02ToWgs84(info.latitude,info.longitude)
return info
}
// 百度坐标系 转 Gcj坐标系
export function bd09tToGcj02(bdLat, bdLon){
let x = bdLon - 0.0065
let y = bdLat - 0.006
let z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * X_PI)
let theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * X_PI)
let ggLng = z * Math.cos(theta)
let ggLat = z * Math.sin(theta)
return {
latitude: ggLat,
longitude: ggLng
}
}
// gcj坐标系转wgs84
export function gcj02ToWgs84(lat, lon) {
let info = {}
let gps = transform(lat, lon)
let longitude = lon * 2 - gps.longitude
let latitude = lat * 2 - gps.latitude
info.longitude = longitude
info.latitude = latitude
return info
}
function transformLon( x, y) {
let ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1
* Math.sqrt(Math.abs(x))
ret += (20.0 * Math.sin(6.0 * x * PI) + 20.0 * Math.sin(2.0 * x * PI)) * 2.0 / 3.0
ret += (20.0 * Math.sin(x * PI) + 40.0 * Math.sin(x / 3.0 * PI)) * 2.0 / 3.0
ret += (150.0 * Math.sin(x / 12.0 * PI) + 300.0 * Math.sin(x / 30.0 * PI)) * 2.0 / 3.0
return ret
}
function transformLat(lng, lat) {
let ret = -100.0 + 2.0 * lng + 3.0 * lat + 0.2 * lat * lat + 0.1 * lng * lat + 0.2 * Math.sqrt(Math.abs(lng))
ret += (20.0 * Math.sin(6.0 * lng * PI) + 20.0 * Math.sin(2.0 * lng * PI)) * 2.0 / 3.0
ret += (20.0 * Math.sin(lat * PI) + 40.0 * Math.sin(lat / 3.0 * PI)) * 2.0 / 3.0
ret += (160.0 * Math.sin(lat / 12.0 * PI) + 320 * Math.sin(lat * PI / 30.0)) * 2.0 / 3.0
return ret
}
function transform(lat, lon) {
let info = {}
let dLat = transformLat(lon - 105.0, lat - 35.0)
let dLon = transformLon(lon - 105.0, lat - 35.0)
let radLat = lat / 180.0 * PI
let magic = Math.sin(radLat)
magic = 1 - EE * magic * magic
let sqrtMagic = Math.sqrt(magic)
dLat = (dLat * 180.0) / ((A * (1 - EE)) / (magic * sqrtMagic) * PI)
dLon = (dLon * 180.0) / (A / sqrtMagic * Math.cos(radLat) * PI)
let mgLat = lat + dLat
let mgLon = lon + dLon
info.latitude = mgLat
info.longitude = mgLon
return info
}

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