python 算法

0x01  列表求和

  s = 0

  for x in seq:
  s += x

 


0x02
 迭代 

  seq1 = [[0, 1], [2], [3, 4, 5]]
  s = 0
  for seq2 in seq1:
    for x in seq2:
      s += x

0x03 树

class Tree:
def __init__(self, left, right):
  self.left = left
  self.right = right

 

 

 

0x04 构造10*10 矩阵

m = [[0]*10]*10

print m

那一个数独 就是  [[0]*9]*9

 

0x05 

sum(f(i)for i in range(m,n+1)

 

0x06 产生一个随机的列表,1-100

 

from random import randrange

seq = [randrange(10*10)for i in range (100)]

 

 

 

 

 

 

 

posted @ 2016-04-20 17:37  Cheetos  阅读(113)  评论(0编辑  收藏  举报