第七次作业

1.P121   1

#include<stdio.h>

main(){

        double m[8];

        int i;

        for(i=0;i<=7;i++)

                 scanf("%lf",&m[i]);

        for(i=7;i>=0;i--)

                 printf("%f",m[i]);

}

 

 

 

 

2.P121   2

#include<stdio.h>

main(){

        double m[6],max;

        int i,f;

        printf("输入\n");

        for(i=0;i<=5;i++)

                 scanf("%lf",&m[i]);

        max=m[0];

        f=0;

        for(i=1;i<=5;i++)

                 if(m[i]>max)

                 {

                         max=m[i];

                         f=i;

                 }

                 printf("最大值%f的下标为%d\n",max,f);

}

 

 

 

3.P121    3

#include<stdio.h>

main(){

        double f[10]={1,1};

        int i,sum;

        sum=f[0]+f[1];

        for(i=2;i<=9;i++)

        {

        f[i]=f[i-1]+f[i-2];

        sum+=f[i];

                 }

                 printf("sum=%d\n",sum);

}

 

 

 

4.P101.6-4.

#include<stdio.h>

main(){

        int a[3][4];

        int i,j;

        printf("请输入12个\n");

        for(i=0;i<=2;i++)

                 for(j=0;j<=3;j++)

                         scanf("%d",&a[i][j]);

                 for(i=0;i<=2;i++)

        {

        for(j=0;j<=3;j++)

                 printf("%4d",a[i][j]);

                 printf("\n");

                 }

}

 

 

 

5.P101 6-5

#include<stdio.h>

main(){

        int i,j,s=0;

        int m[5][5]={{1,2,3,4,5},

        {6,7,8,9,10},

        {11,12,13,14,15},

        {16,17,18,19,20},

        {21,22,23,24,25}};

        for(i=0;i<=4;i++)

                 for(j=0;j<=4;j++)

                         if(i==j||i+j==4)

                                  s+=m[i][j];

                         printf("s=%d\n",s);

}

 

 

 

6.P78   1

#include<stdio.h>

main(){

        float s[5],a=0;

        int i;

        printf("输入\n");

        for(i=0;i<=4;i++)

        {

                 scanf("%f",&s[i]);

        a+=s[i];

        }

        a/=5;

        printf("平均%.2f\n",a);

}

 

 

 

7.P78    2.

#include<stdio.h>

main(){

        int m[7]={56,75,15,46,98,35,68};

        int i,j,t;

        printf("原有数据\n");

        for(i=0;i<=6;i++)

                 printf("%3d",m[i]);

        printf("\n");

        for(i=0,j=6;i<=j;i++,j--)

        {

                 t=m[i];m[i]=m[j];m[j]=t;

        }

        printf("调换后\n");

        for(i=0;i<=6;i++)

                 printf("%3d",m[i]);

        printf("\n");

}

 

 

posted @ 2021-12-08 21:04  澄憕  阅读(34)  评论(0)    收藏  举报