C-CODE

摘要： View Code programvarbeginread();readln();for i:=1 to 2 dobeginend;write();end. 阅读全文

摘要： 完全背包:Piggy-Bank猪猪储蓄罐Time Limit:1000MS Memory Limit:65536KTotal Submit:14 Accepted:6DescriptionBefore ACM can do anything, a budget must be prepared and the necessary financial support obtained.ACM要正常运转的前提，准备并提供好一定的财务预算费用是必需的。The main income for this action comes from Irreversibly Bound Money (IBM).这 阅读全文

摘要： 题目：01背包：Bone Collector骨骼收集家Time Limit:1000MS Memory Limit:65536KTotal Submit:44 Accepted:7DescriptionMany years ago , in Teddy’s hometown there was a man who was called “Bone Collector”.许多年前，在泰迪镇有这么一个骨骼收集家。This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave … 阅读全文

摘要： 题目：【培训习题．动态规划】8.7pasture三角形牧场Time Limit:1000MS Memory Limit:65536KTotal Submit:32 Accepted:6Description和所有人一样，奶牛喜欢变化。它们正在设想新造型的牧场。奶牛建筑师Hei想建造围有漂亮白色栅栏的三角形牧场。她拥有N(3≤N≤40)块木板，每块的长度Li(1≤Li≤40)都是整数，她想用所有的木板围成一个三角形使得牧场面积最大。请帮助Hei小姐构造这样的牧场，并计算出这个最大牧场的面积。Input第1行：一个整数N第2..N+1行：每行包含一个整数，即是木板长度。Output仅一个整数：最大 阅读全文

摘要： 题目：代码：#include<stdio.h> #include<stdlib.h> int f[501][501]={0},value[501]={0},book[501]={0},ans[501][501]={0}; int n,k; int max(int a,int b) { if(a>b)return a; return b; } int min(int a,int b) { if(a<b)return a; return b; } void printf_ans(int i,int e) { int j; if(i==1){ printf(&qu 阅读全文

摘要： 题目：http://60.191.162.158:8080/JudgeOnline/showproblem?problem_id=1230代码：#include<stdio.h> int f[10001]={0},task[10001][3]={0},time[10001][3]={0}; int main() { int n,k,i,j,p; scanf("%d%d",&n,&k); p=0; for(i=1;i<=k;i++){ scanf("%d %d",&task[i][1],&task[i][2 阅读全文

摘要： #include<stdio.h> #include<string.h> #include<stdlib.h> #include<math.h> int bs(int a){ if(a<0)return -a; return a; } int min (int a,int b,int c){ int temp; temp=b; if(a<b)temp=a; if(c<temp)temp=c; return temp; } int f[2001][2001]={0}; int main() { int i,j,k,l1,l2... 阅读全文