task4

code

#include <stdio.h>
#include <string.h>
#define N 5
#define M 80
int main() {
    char songs[N][M];

    FILE* fp;
    fp = fopen("data1.txt", "r");
    if (fp == NULL) {
        printf("fail to open file\n");
        return 1;
    }
    int t = 0;
    char h;
    while (1) {
        h = fgetc(fp);
        if (h == EOF) {
            break;
        }
        else if (h == ' ' || h == '\n') {
            continue;
        }
        else {
            t++;
        }
    }

    printf("文件内字符数为%d\n", t);

    fclose(fp);
    return 0;
}

test

 

task5

code

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#define N 10
typedef struct {
    long int id;
    char name[20];
    float objective; // 客观题得分
    float subjective; // 操作题得分
    float sum; // 总分
    char ans[10]; // 考试结果
} STU;
// 函数声明
void finput(STU st[], int n);
void foutput(STU st[], int n);
void output(STU st[], int n);
int process(STU st[], int n, STU st_pass[]);
int main() {
    STU stu[N], stu_pass[N];
    int cnt;
    double pass_rate;
    printf("从文件读入%d个考生信息...\n", N);
    finput(stu, N);
    printf("\n对考生成绩进行统计...\n");
    cnt = process(stu, N, stu_pass);
    printf("\n通过考试的名单:\n");
    output(stu, N); // 输出到屏幕
    foutput(stu, N); // 输出到文件
    pass_rate = 1.0 * cnt / N;
    printf("\n本次等级考试通过率: %.2f%%\n", pass_rate * 100);
    return 0;
}
// 把通过考试的考生完整信息输出到屏幕上
// 准考证号,姓名,客观题得分,操作题得分,总分,结果
void output(STU st[], int n) {
    int i;
    printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n");
    for (i = 0; i < n; i++)
        printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", st[i].id,
            st[i].name, st[i].objective, st[i].subjective, st[i].sum, st[i].ans);
}
// 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分
void finput(STU st[], int n) {
    int i;
    FILE* fin;
    fin = fopen("examinee.txt", "r");
    if (fin == NULL) {
        printf("fail to open file\n");
        exit(0);
    }
    while (!feof(fin)) {
        for (i = 0; i < n; i++)
            fscanf(fin, "%ld %s %f %f", &st[i].id, st[i].name,
                &st[i].objective, &st[i].subjective);
    }
    fclose(fin);
}
// 把通过考试的考生完整信息写入文件list_pass.txt
// 准考证号,姓名,客观题得分,操作题得分,总分,结果
void foutput(STU s[], int n) {
    FILE* fout;
    int i;
    // 保存到文件
    fout = fopen("list_pass.txt", "w");
    if (!fout) {
        printf("fail to open or create list_pass.txt\n");
        exit(0);
    }
    fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n");
    for (i = 0; i < n; i++)
        fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id,
            s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].ans);
    fclose(fout);
}
// 对考生信息进行处理:计算每位考生考试总分、结果;统计考试通过的人数
int process(STU st[], int n, STU st_pass[]) {
    FILE* fscore;
    int cnt = 0;
    fscore = fopen("list_pass.txt", "r");
    for (int i = 0; i < n; i++) {
        st[i].sum = st[i].objective + st[i].subjective;
    }

    for (int i = 0; i < n; i++) {
        if (st[i].sum >= 60) {
            strcpy(st[i].ans, "pass");
            cnt++;
        }
        else {
            strcpy(st[i].ans, "fail");
        }
    }

    return cnt;
}

test

 

task6

code

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define N 80

typedef struct {
    int id;
    char name[20];
    char class[100];
}info;


void finput(info stu[], int n) {

    FILE* fp;
    fp = fopen("list.txt", "r");
    while (!feof(fp)) {
        for (int i = 0; i < N; i++) {
            fscanf(fp, "%d%s%s", &stu[i].id, stu[i].name, stu[i].class);
        }
    }
    fclose(fp);
}

void output(info stu[], int n) {
    for (int i = 0; i < n; i++)
        printf("%d\t%s\t%s\n", stu[i].id, stu[i].name, stu[i].class);
}

void translate(info stu[], info sts[], int n) {
    srand((unsigned)time(NULL));
    int judge[80] = { 0 };
    for (int i = 0; i < 5; i++) {
        int j = rand() % 80 + 1;
        if (judge[j] == 1) {
            i--;
            continue;
        }
        sts[i].id = stu[j].id;
        strcpy(sts[i].name, stu[j].name);
        strcpy(sts[i].class, stu[j].class);
        judge[j] = 1;
    }
}

void sort(info sts[], int n) {
    for (int i = 0; i < 5; i++) {
        for (int j = i; j < 5; j++) {
            if (sts[i].id > sts[j].id) {
                int l = sts[i].id;
                sts[i].id = sts[j].id;
                sts[j].id = l;
                char p[100];
                strcpy(p, sts[i].name);
                strcpy(sts[i].name, sts[j].name);
                strcpy(sts[j].name, p);
            }
        }
    }
}

int main()
{
    info stu[N], sts[5];
    finput(stu, N);
    output(stu, N);
    printf("\n");
    translate(stu, sts, N);
    sort(sts, 5);
    output(sts, 5);

    return 0;
}

test

 

posted on 2023-12-21 10:12  Bulletproof_Picasso  阅读(3)  评论(0编辑  收藏  举报