python一元二次方程解

python一元二次方程解

import math

def quadratic(a,b, c):
    jie=()
    if a == 0:
        print("a为分母，不能为0")
    elif (b ** 2 - 4 * a * c) < 0:
        jie=("无解") 
        return (jie)
        print("x无解")
    elif (b ** 2 - 4 * a * c) == 0:
        x1=-b/2/a
        jie=(x1)
        return (jie)
    else:
        x1 = -(math.sqrt((b * b - 4 * a * c) / (4 * a * a))) - (b / (2 * a))
        x2 = (math.sqrt((b * b - 4 * a * c) /( 4 * a * a))) - (b / (2 * a))
        jie=(x2,x1)
        print(jie)
        return (jie)

quadratic(2,3,1)